5 x + 3 y = 41 / * 3
3 x + 2 y = 26 / * ( - 5 )
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15 x + 9 y = 123
+
- 15 x - 10 y = - 130
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- y = - 7 / * ( - 1 )
y = 7
Answer:
Each program costs D ) $7
Average = mean = sum of the values / number of data
Values = h, j, and k
Number of data = 3
Sum of the values = h + j + k
Mean = [h + j + k] / 3
=> Answer: option c. [h+j+k] over 3
To simplify this, you would have to turn b^-2 into a positive exponent.
To do this, we have to flip b^-2, which would get rid of the negate from the exponent: -2
3a^4 b^-2 c^3 / b^-2
Then we get the answer:
3a^4 c^3
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b^-2
I have a picture to clarify!
I hope this helped, let me know if you don't understand! ^.^