Answer:
Cost of a coffee is <u>$2.5</u> and cost of a latte is <u>$4.25.</u>
Step-by-step explanation:
Let cost of 1 coffee be 'c' and cost of 1 latte be 'l' dollars.
Given:
4 coffees and 12 lattes cost $61.
12 coffees and 7 lattes cost $59.75.
∵ 1 coffee cost = ![c](https://tex.z-dn.net/?f=c)
∴ 4 coffees cost =
and 12 coffee cost = ![12c](https://tex.z-dn.net/?f=12c)
∵ 1 latte cost = ![l](https://tex.z-dn.net/?f=l)
∴ 12 lattes cost =
and 7 lattes cost = ![7l](https://tex.z-dn.net/?f=7l)
Now, as per question:
![4c+12l=61-----1\\12c+7l=59.75----2](https://tex.z-dn.net/?f=4c%2B12l%3D61-----1%5C%5C12c%2B7l%3D59.75----2)
Now, multiplying equation (1) by -3 and adding the result to equation (2). This gives,
![-3(4c+12l)=-3(61)\\\\-12c-36l=-183\\12c+7l=59.75\\+\\----------\\0-29l=-123.25\\\\l=\frac{-123.25}{-29}=\$4.25](https://tex.z-dn.net/?f=-3%284c%2B12l%29%3D-3%2861%29%5C%5C%5C%5C-12c-36l%3D-183%5C%5C12c%2B7l%3D59.75%5C%5C%2B%5C%5C----------%5C%5C0-29l%3D-123.25%5C%5C%5C%5Cl%3D%5Cfrac%7B-123.25%7D%7B-29%7D%3D%5C%244.25)
Now, plug in the value of 'l' in equation 1 to solve for 'c'. This gives,
![4c+12(4.25)=61\\\\4c+51=61\\\\4c=61-51\\\\4c=10\\\\c=\frac{10}{4}=\$2.5](https://tex.z-dn.net/?f=4c%2B12%284.25%29%3D61%5C%5C%5C%5C4c%2B51%3D61%5C%5C%5C%5C4c%3D61-51%5C%5C%5C%5C4c%3D10%5C%5C%5C%5Cc%3D%5Cfrac%7B10%7D%7B4%7D%3D%5C%242.5)
Therefore, cost of a coffee is $2.5 and cost of a latte is $4.25.
Answer: 789.39
Step-by-step explanation: Just subtract 89.51 from 878.9.
Mark Brainliest if this helped!
Answer: 170
Steps:
Range- the difference between the greatest and smallest value of a data set.
546 - 376 = 170
Answer:
YES YES HE VENTED ITS NOT ME DONT WORRY
Use the fact that the sum of interior angles of a triangle is equal to 180°.
Hence, the second and the third angles of the given triangle are 180-115/2= 65/2<span>
(32 degrees and 30 minutes).</span>