All categories

2 years ago

Points to the first 5 people to answer this question ·,

Mathematics

2 answers:

Anna35 [415]2 years ago

6 0

Answer:

Step-by-step explanation:

uh.

DaniilM [7]2 years ago

4 0

Answer:

Step-by-step explanation:

You might be interested in

Please help. 20 points. Show all work. Thank you.

Bogdan [553]

The lateral area of a cone is the surface area (aka area of the sides of the object) minus the area of the base of the cone.

The equation for the lateral area of a cone is: $lateral \: area = \pi rl$
where r = radius and l = slant height.

Since you know that the lateral area = $500 \pi \: cm^{2}$ and the radius, r = 50 cm, you can plug those values into the equation for the lateral area and solve for l, the slant height:
$lateral \: area = \pi rl\\
500 \pi = \pi (50)(l)\\
500 = 50l\\
l = 10$

The slant height of the cone is A) 10cm.

5 0

3 years ago

Which inequality is represented by the graph?

blsea [12.9K]

Answer:

B: 4/5x -2y ≥ 3

Step-by-step explanation:

The first thing I always look for is the y-intercept which in this case is around -1.5 (- $1\frac{1}{2}$ ). That will be your constant (b) in y = mx + b. Then calculate the slope which will be your m in the equation. Visually, I would estimate it is around $\frac{2}{5}$ . So now, your equation is y = $\frac{2}{5}$ x -1 $\frac{1}{2\\}$ . Next we want to figure out what the inequality will be. The shaded part is underneath the line, which means that y must be less than where the line is. Therefore the inequality will be y ≤ $\frac{2}{5}$ x -1 $\frac{1}{2\\}$ .

Now in this question, the answers available are not in this form. The next step would be to multiply every part of the inequality by 2 (it is essential that all parts are multiplied) so that you get 2y ≤ $\frac{4}{5}$ x -3. The last step is to rearrange the inequality so that it matches the answers on the question.

3 ≤ $\frac{4}{5}$ x - 2y

$\frac{4}{5}$ x - 2y ≥ 3

7 0

3 years ago

Find the solution r(t)r(t) of the differential equation with the given initial condition: r′(t)=⟨sin9t,sin6t,9t⟩,r(0)=⟨4,6,3⟩

klemol [59]

$\mathbf r'(t)=\langle\sin9t,\sin6t,9t\rangle$

$\mathbf r(t)=\displaystyle\int\mathbf r'(t)\,\mathrm dt$

$\mathbf r(t)=\left\langle\displaystyle\int\sin9t\,\mathrm dt,\int\sin6t\,\mathrm dt,\int9t\,\mathrm dt\right\rangle$

$\displaystyle\int\sin9t\,\mathrm dt=\frac19\cos9t+C_1$

$\displaystyle\int\sin6t\,\mathrm dt=\frac16\cos6t+C_2$

$\displaystyle\int9t\,\mathrm dt=\frac92t^2+C_3$

With the initial condition $\mathbf r(0)=\langle4,6,3\rangle$ , we find

$\dfrac19\cos0+C_1=4\implies C_1=\dfrac{35}9$

$\dfrac16\cos0+C_2=6\implies C_2=\dfrac{35}6$

$\dfrac92\cdot0^2+C_3=3\implies C_3=3$

So the particular solution to the IVP is

$\mathbf r(t)=\left\langle\dfrac19\cos9t+\dfrac{35}9,\dfrac16\cos6t+\dfrac{35}6,\dfrac92t^2+3\right\rangle$

4 0

3 years ago

The value of V is double the value of Q.

makvit [3.9K]

Answer:

v = 2q

Step-by-step explanation:

If this is all is given in the question, then the answer is an equation. If there are numbers given, then plug the numbers into the equation to solve.

4 0

2 years ago

What is the area PLEASE HELP!! :/

UkoKoshka [18]

Answer:

15 square meters

Step-by-step explanation:

when it says find the area you have to add all the lengths together

4 0

2 years ago