Answer:
Step-by-step explanation:
hello :
an Degree 3 polynomial with zeros 4, 6, and -2 is :
f(x) = (x-4)(x-6)(x+2)
all polynomial are : a (x-4)(x-6)(x+2) a ≠ 0
Answer: x=-2 y=2
Step-by-step explanation:
I decided that isolating the y value of the second equation is the best way to start solving.
I divide 3 from both sides to get y= (4-x)/3. With this, I can substitute into the first equation. 4x+3(4-x)/3)=-2.
The multiplying the 3 by the denominator three cancels each other out to make:
4x+4-x=-2.
We subtract 4 on both sides and then subtract x from 4x.
We end up with 3x=-6. Then, we divide both sides by 3.
x=-2.
Now we substitute this into the second equation to solve.
3y=4-(-2)
This becomes 3y=4+2 which is 3y=6
We divide both sides by 3 to get y=2
We end up with x=-2 and y=2.
I hope you learned something :)
Are you asking what is 248-200? If so that would be 48. 200-248=248
Write the decimal number as a fraction
(over 1)
0.87 = 0.87 / 1
Multiplying by 1 to eliminate 2 decimal places
we multiply top and bottom by 2 10's
Numerator (N)
N = 0.87 × 10 × 10 = 87
Denominator (D)
D = 1 × 10 × 10 = 100
N / D = 87 / 100
Simplifying our fraction
= 87/100
<span>= 87/100</span>
