<img src="https://tex.z-dn.net/?f=%20%28-%20%20%5Cfrac%7B%20%7B1%7D%5E%7B2%7D%20%7D%7B3%7D%20%29%20%2B%20%20%5Cfrac%7B5%7D%7B6%7

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3 years ago

D%20%28%20-%20%20%5Cfrac%7B1%7D%7B2%7D%20%29" id="TexFormula1" title=" (- \frac{ {1}^{2} }{3} ) + \frac{5}{6} ( - \frac{1}{2} )" alt=" (- \frac{ {1}^{2} }{3} ) + \frac{5}{6} ( - \frac{1}{2} )" align="absmiddle" class="latex-formula">

Mathematics

1 answer:

coldgirl [10]3 years ago

5 0

Answer:

$-\frac{3}{4}$

Step-by-step explanation:

$(-\frac{1^{2}}{3}})+\frac{5}{6}(-\frac{1}{2}) =-\frac{1}{3} -\frac{5}{12} =-\frac{3}{4}$

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PLEASE HELP ASAP!!! (ii only)

mixer [17]

The equation of the tangent line can be found using slope formula and fact that slope = dy/dx.

$\frac{dy}{dx} = \frac{y - y_0}{x - x_0}$

where (x0,y0) is point A ---> (0,-1)

Then rearrange equation into slope-intercept form:
$y = \frac{dy}{dx}(x - 0) -1$

Finally sub in x=0 into dy/dx to get slope at the point (0,-1)

$y = 3x -1$