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bezimeni [28]
3 years ago
7

How many mm Hg are there in 2.27 atm?

Chemistry
1 answer:
vekshin13 years ago
3 0

Answer:

\huge\boxed{\sf 2.27\ atm = 1,725\ mm\ of\ Hg}

Explanation:

We know that:

1 atm = 760 mm of Hg (Standardly)

Multiply both sides by 2.27

2.27 atm = 760 * 2.27 mm of Hg

2.27 atm = 1,725 mm of Hg

\rule[225]{225}{2}

Hope this helped!

<h3>~AH1807</h3>
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Answer : The ratio of the mass ratio of S to O in SO to the mass ratio of S to O in SO₂ is 2.

Explanation :

Law of multiple proportion : It states that when two elements can combine to form two or more different compounds then the mass of one element compared to fixed mass of the other will always be in a ratio of small whole numbers.

As we know that,

Mass of oxygen = 16 g

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Mass of sulfur in SO = 32 g

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Mass ratio of Sulfur to oxygen in SO = \frac{\text{Mass of sulfur}}{\text{Mass of oxygen}}=\frac{32g}{16g}=2     .....(1)

and,

Mass of sulfur in SO₂= 32 g

Mass of oxygen in SO₂  = (2 × 16)g = 32 g

Mass ratio of Sulfur to oxygen in SO₂ = \frac{\text{Mass of sulfur}}{\text{Mass of oxygen}}=\frac{32g}{32g}=1     .....(1)

Ratio of S and O in SO = 2 : 1

Ratio of S and O in SO₂ = 1 : 1

Taking ratio of 1 and 2, we get:

\frac{\text{Mass ratio of Sulfur to oxygen in SO}}{\text{Mass ratio of Sulfur to oxygen in }SO_2}=\frac{2}{1}=2

Hence, the ratio of the mass ratio of S to O in SO to the mass ratio of S to O in SO₂ is 2.

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3 years ago
_FeCl3+_NaOH=Fe(OH)3+NaCl
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Answer:

This is the balanced equation for that:

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3 years ago
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