Assume that you measured exactly 2.0 mL of the sodium chloride solution into a small test tube. How many moles of sodium chlorid
2 answers:
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Answer:
Explanation:
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In this case, according to the given chemical reaction, it is first necessary to compute the moles of reacting LiOH given its molar mass:
Thus, since there is a 1:1 mole ratio between lithium hydroxide and silver nitrate (169.87 g/mol) the resulting milligrams turn out to be:
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Answer:
Explanation:
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In this case, for the dissociation of the sodium hydroxide into sodium and hydroxyl ions we have:
Which is a 100% dissociation as sodium hydroxide is a strong base, therefore, the concentration of the hydroxyl ions are 1.0x10⁻⁹. For that reason, the pOH could be computed as:
Finally, from the definition of pH, we have:
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