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Rudik [331]
2 years ago
7

What might be a scientific question

Chemistry
1 answer:
AURORKA [14]2 years ago
3 0

Answer:

Example of a scientific question:

Does the angle of a ramp change the distance a toy car will travel?

Explanation:

You might be interested in
A 10g vial must have 45ml of diluent added to it. it has a powder volume of 5ml. how many mgr will be in each ml of the final so
Semenov [28]

The solution has a concentration 20 mgr in each mL of the final solution.

To solve this problem, we need to know about concentration. The concentration formula can be defined as how much the mass per unit volume is. It can be written as

M = m/V

where M is concentration, m is mass of solute, V is the total volume of solution.

From the text we know that :

m = 10g

vsolvent = 45mL

vsolute = 5 mL

find the total volume (V)

V = vsolvent + vsolute

V = 45 + 5

V = 50mL

Then, find the concentration

M = m/V

M = 10gr / 50 mL

M = 1000 mgr / 50mL

M = 20 mgr / mL

Hence, the solution has a concentration 20 mgr in each mL of the final solution.

Find more on concentration at: brainly.com/question/17206790

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6 0
2 years ago
Citric acid is a naturally occurring compound. what orbitals are used to form each indicated bond? be sure to answer all parts.2
Rina8888 [55]

Answer : The orbitals that are used to form each indicated bond in citric acid is given below as per the attachment.

Answer 1) σ Bond a : C has SP^{2}  O has SP^{2} .

Explanation : The orbitals of oxygen and carbon which are involved in SP^{2} hybridization to form sigma bonds. This is observed at 'a' position in the citric acid molecule.

Answer 2) π Bond a: C has π orbitals and  O also has π  orbitals.

Explanation : The pi-bond at the 'a'position has carbon and oxygen atoms which undergoes pi-bond formation. And has pi orbitals of oxygen and carbon involved in the bonding process.

Answer 3) Bond b:  O SP^{3}  H has only S orbital involved in bonding.

Explanation : The bonding at 'b' position involves oxygen SP^{3} hydrogen atoms in it. It has SP^{3} hybridized orbitals and S orbital of hydrogen involved in the bonding.

Answer 4) Bond c:   C is SP^{3}  O is also SP^{3}

Explanation : The bonding involved at 'c' position has carbon and oxygen atoms involved in it. Both the atoms involves the orbitals of SP^{3} hybridized bonds.

Answer 5) Bond d:   C atom has SP^{3}  C atom has SP^{3}

Explanation : At the position of 'd' the bonding between two carbon atoms is found to be SP^{3}. Therefore, the orbitals that undergo SP^{3} hybridization are SP^{3}.

Answer 6) Bond e : C1 containing O SP^{2}    

C2 is SP^{3}

Explanation : The carbon atom which contains oxygen along with a double bond has SP^{2} hybridized orbitals involved in the bonding process; whereas the carbon at C2 has SP^{3} hybridized orbitals involved during the bonding. This is for the 'e' position.

7 0
3 years ago
My theoretical yield of beryllium chloride was 10.7 grams. If my actual yield was 4.5 grams, what was my percent yield?
artcher [175]

Answer:

The percent yield of this reaction is 42.1 % (option B)

Explanation:

Step 1: Data given

Theoretical yield of beryllium chloride = 10.7 grams

actual yield of beryllium chloride = 4.5 grams

Step 2: Calculate the percent yield for this reaction

Percent yield = (actual yield / theoretical yield) * 100%

Percent yield = (4.5 grams / 10.7 grams ) * 100 %

Percent yield = 42.1 %

The percent yield of this reaction is 42.1 % (option B)

6 0
3 years ago
How do we balance a chemical equation 4 marks?.
Vesna [10]

To balance a chemical equation, place coefficient as needed in front of the symbols or formulas of the elements. So the same number of each type of atom occurs in both reactants and products.

Steps to be followed are-

(1) Write down the chemical reaction in the form of word equation, keeping all the reactants on left hand side and keeping products on right hand side.

(2) Write all the symbol and formula of all reactants and products in word equation.

(3) Balance the whole equation by multiplying the symbols and formula by smallest possible figures.

Same number of each and every atom, of same type occurs in both reactants and products.

Once all the individual elements are balanced, then the total number of atoms of each element on the reactant and product side are compared once again after balancing. If there are no inequalities, the chemical equation is said to be balanced.

To learn more about balancing chemical equations visit the link- brainly.com/question/26227625

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6 0
1 year ago
What mass of lead (density 11.4 g/cm3) would have an identical volume to 20.1 g of mercury (density 13.6 g/cm3)?
oksano4ka [1.4K]
In order to determine the mass of lead, Pb, that would have an identical volume as 20.1 g of mercury, Hg, we first get the equivalent volume of 20.1 g of mercury. This can be done by using the given density of mercury which is equal to 13.6 g/cm^3. This is shown in the following equation:

20.1 g Hg/ 13.6g/cm^3 = 1.4779 cm^3 of Hg

Consequently, we use this obtained volume which is the target volume for lead. Again, we make use of the density of the substance, in this case, lead has a density of 11.4 g/cm^3. The resulting equation is then:

11.4 g/cm^3 x 1.4779 cm^3 = 16.8485 g of Pb

Thus, the amount of lead that has an identical volume as 20.1 g of mercury is 16.8485 g Pb.   
8 0
3 years ago
Read 2 more answers
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