Answer:
D. 4x as much
Explanation:
The answer is pretty simple. The question is asking about 10m/s and 20m/s right? Take a look at the energy at each point on the graph. At 10m/s the kinetic energy is 100 on the graph. At 20m/s the kinetic energy is 400. You'll notice that 100 x 4 is 400 - That's the answer.
You can also prove this mathematically. The formula for kinetic energy is
The question says: constant mass so we can ignore that for now.
(1/2) * 10^2 is (1/2) * 100 = 50
for the 20m/s ball it would be
(1/2) * 20^2 = 400 * 1/2 = 200
Once again, you see that it is 4x
Answer:
False
Explanation:
BugTraq is a high volume, full disclosure mailing list for the detailed discussion and announcement of computer security vulnerabilities, not US-CERT
Answer:
Here is the Python program:
COOKIES_PER_BAG = 40 #sets constant value for bag of cookies
SERVINGS_PER_BAG = 10 #sets constant value for serving in bag
CALORIES_PER_SERVING = 300 #sets constant value servings per bag
cookies = int(input("How many cookies did you eat? ")) #prompts user to input how many cookies he or she ate
totalCalories = cookies * (CALORIES_PER_SERVING / (COOKIES_PER_BAG / SERVINGS_PER_BAG)); #computes total calories consumed by user
print("Total calories consumed:",totalCalories) #displays the computed value of totalCalories consumed
Explanation:
The algorithm is:
- Start
- Declare constants COOKIES_PER_BAG, SERVINGS_PER_BAG and CALORIES_PER_SERVING
- Set COOKIES_PER_BAG to 40
- Set SERVINGS_PER_BAG to 10
- Set CALORIES_PER_SERVING to 300
- Input cookies
- Calculate totalCalories: totalCalories ← cookies * (CALORIES_PER_SERVING / (COOKIES_PER_BAG / SERVINGS_PER_BAG))
- Display totalCalories
I will explain the program with an example:
Lets say user enters 5 as cookies he or she ate so
cookies = 5
Now total calories are computed as:
totalCalories = cookies * (CALORIES_PER_SERVING / (COOKIES_PER_BAG / SERVINGS_PER_BAG));
This becomes:
totalCalories = 5 * (300/40/10)
totalCalories = 5 * (300/4)
totalCalories = 5 * 75
totalCalories = 375
The screenshot of program along with its output is attached.
Answer:
A. 50 percent
Explanation:
The correct option is - A. 50 percent
Another preventive measure you can take is to maintain the relative humidity at around 50 percent. Be careful not to increase the humidity too far—to the point where moisture starts to condense on the equipment.
