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Alexxandr [17]
3 years ago
9

Evan spent 20 hours doing homework last week. This week he spent 25 hours doing homework. He says that he spent 125% more time d

oing homework this week. Is he correct? Show your work to justify your decision
Mathematics
2 answers:
USPshnik [31]3 years ago
8 0

Answer:

The correct answer should be <u>No</u>

nadya68 [22]3 years ago
5 0

Answer:

No

Step-by-step explanation:

Because he did not spend that much more time on it

He only spent 5 more % than last week

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The width of a rectangle is 5 more than twice the length. the perimeter of the rectangle is 28 in. what is the length and width
ycow [4]

Perimeter is P = 2l + 2w. From the question you know that w = 2l + 5 and that P = 28. To find l, plug the expression for w into the perimeter equation:

28 = 2l + 2(2l + 5) 

28 = 2l + 4l + 10

28 = 6l + 10

18 = 6l

3 = l

Now find w by plugging 3 into its equation - w = 2(3) + 5. w = 11

Lastly, check your work by plugging everything back into the perimeter equation:  28 = 2(3) + 2(11), which is 28 = 6 + 22. Correct! So the length is 3 in and the width is 11 in.

5 0
3 years ago
Pls help me i only have 5 minutes
V125BC [204]

Give instructions about sound, lighting etc

5 0
3 years ago
What operation would you perform first ,and then second when solving for m in the following equation .
Salsk061 [2.6K]

Answer:

dont remember the property names but subtract 10 on both sides then divide by 7 on both sides

4 0
3 years ago
Jim picks a number he doubles that number then adds five and gets 41 as his results what was the original number Jim picked
KiRa [710]
18 because u take 41 -5=36 then divide that and get 36 divided by 2 =18 and that's the answer u would start off with
6 0
3 years ago
Solve the polynomial equation
ExtremeBDS [4]
Hey there!

You can solve this by squaring both sides to first cancel out the square root on the left. Then, you can eliminate each term as your normally would. 

2 \sqrt{x} =x-3

(2 \sqrt{x})^{2}  = (x-3)^{2}

(4x) = (x-3)(x-3)

4x =  x^{2} -6x+9

x^{2} -10x+9

Now, you're given the opportunity to find your solution using the quadratic formula. That formula is:

\frac{-b_-^+ \sqrt{b^2-4ac} }{2a}

You can find out a, b, and c by comparing your new equation to the standard form. Luckily, we just put our equation into standard form:

ax^{2} + bx + c

x^{2} -10x+9

a = 1 \\ b = -10  \\ c = 9

To find your solution, plug these numbers into the quadratic formula and solve. 

\frac{-b_-^+ \sqrt{b^2-4ac} }{2a}

\frac{10_-^+ \sqrt{-10^2-4(9)}}{2}

Remember to use PEMDAS when solving these problems. 

\frac{10_-^+ \sqrt{100-36}}{2}

\frac{10_-^+ \sqrt{64}}{2}

\frac{10_-^+ 8}{2}

Now, solve this final bit by adding the top terms then subtracting them for two different answers. 

\frac{10 + 8}{2} = 9

\frac{10- 8}{2} = 1

Don't assume that both of these are correct. The very last step is to plug both of these into the original problem you were given and see if they make the equation true. 

2 \sqrt{9} =9-3
2*3=6
6=6

2 \sqrt{1} =1-3
2*1=-2
2 \neq -2

So (finally), your answer will be x = 9. 

Hope this helped you out! :-)
7 0
4 years ago
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