ANSWER
Alex needs to mix one pound of dried fruit with
![1 \frac{1}{9}](https://tex.z-dn.net/?f=1%20%5Cfrac%7B1%7D%7B9%7D%20)
pounds of walnuts.
EXPLANATION
It was given that, Alex mixes
![\frac{2}{3}](https://tex.z-dn.net/?f=%20%5Cfrac%7B2%7D%7B3%7D)
pounds of walnuts with
![\frac{3}{5}](https://tex.z-dn.net/?f=%20%5Cfrac%7B3%7D%7B5%7D%20)
pounds of dried fruit.
We can write the ratio,
![\frac{2}{3} : \frac{3}{5}](https://tex.z-dn.net/?f=%20%5Cfrac%7B2%7D%7B3%7D%20%3A%20%20%5Cfrac%7B3%7D%7B5%7D%20)
Let
![x](https://tex.z-dn.net/?f=x)
represent how many pounds of walnuts Alex needs to mix with one pound of dried fruit.
Then we can again write the ratio,
![x: 1](https://tex.z-dn.net/?f=x%3A%201)
We can therefore write the proportion,
![\frac{2}{3} : \frac{3}{5} = x: 1](https://tex.z-dn.net/?f=%20%5Cfrac%7B2%7D%7B3%7D%20%3A%20%20%5Cfrac%7B3%7D%7B5%7D%20%20%3D%20x%3A%201)
This can be rewritten as,
![\frac{ \frac{2}{3} }{ \frac{3}{5} } = \frac{x}{1}](https://tex.z-dn.net/?f=%20%5Cfrac%7B%20%5Cfrac%7B2%7D%7B3%7D%20%7D%7B%20%5Cfrac%7B3%7D%7B5%7D%20%7D%20%20%3D%20%20%5Cfrac%7Bx%7D%7B1%7D%20)
We solve for x to obtain,
![\frac{2}{3} \times \frac{5}{3} = x](https://tex.z-dn.net/?f=%20%5Cfrac%7B2%7D%7B3%7D%20%20%5Ctimes%20%20%5Cfrac%7B5%7D%7B3%7D%20%20%3D%20x)
This implies that,
![x = \frac{10}{9}](https://tex.z-dn.net/?f=x%20%3D%20%20%5Cfrac%7B10%7D%7B9%7D%20)
![x = 1 \frac{1}{9}](https://tex.z-dn.net/?f=x%20%3D%201%20%5Cfrac%7B1%7D%7B9%7D%20)
Hence Alex needs to mix
![1\frac{1}{9}](https://tex.z-dn.net/?f=%201%5Cfrac%7B1%7D%7B9%7D%20)
pounds of walnuts with one pound of dried fruit.