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2 years ago

What are the two types of reactions that are needed for PS to even begin?

Biology

1 answer:

Lana71 [14]2 years ago

3 0

Light-dependent reactions and the Calvin cycle light-independent reactions.

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Herbicides are being used to kill weeds in a nearby field. The plants absorb the herbicides from the soil. Which organelle in th

gavmur [86]

Answer: The correct answer is Vacuole

Explanation:

The vacuole is an organelle found in the central portion of plant cells, and is usually filled with cell sap that acts as a "store house" for many substances entering into the cell.

Therefore, the herbicide waste absorbed by the plants will be stored in the VACUOLE.

6 0

3 years ago

Read 2 more answers

Part C Firefly luciferase is the enzyme that allows fireflies to illuminate their abdomens. Because this light generation is an

Bumek [7]

Answer:

K = 9.620 × 10⁻⁶

Explanation:

From the given information:

Temperature T= 6° C

= (273 + 6)K

= 279 K

The correct and well presentation of the reactions are:

1. $Luciferin + O_2$ ⇆ oxyluciferin + light ΔG₁°

2. ATP ⇄ AMP + PP $_i$ ΔG₂° = -31.6 kJ/mol

The overall ΔG° = -4.80 kJ/mol

Let's first determine the ΔG₁° for the equation (1)

ΔG° = ΔG₁° + ΔG₂°

- ΔG₁° = - ΔG° + ΔG₂°

ΔG₁° = ΔG° - ΔG₂°

ΔG₁° = ( -4.80 - (-31.6) ) kJ/mol

ΔG₁° = 26.8 kJ/mol

Using the formula:

ΔG° = -RTIn K

$In \ K =\dfrac{-\Delta G^0}{RT} \\ \\ log \ K = -\dfrac{\Delta G^0}{2.303RT}$

$log \ K = -\dfrac{\Delta G_1^0}{2.303RT} \\ \\ log \ K = -\dfrac{26.8 \times 10^3 \ J/mol}{2.303\times 8.314 \ J/mol/K \times 279 \ K} \\ \\ log \ K =- 5.017$

K = antilog (-5.017)

K = 9.620 × 10⁻⁶

6 0

3 years ago

explain what DNA is and how the model of DNA developed .You should include information on how genetic information is carried ,as

jolli1 [7]

Answer:

DNA is a Deoxyribose nucleic acid and our Dna strand is double helix

Explanation:

I kow this because if you close you see two strands

7 0

3 years ago

In a hardy-weinberg population with two alleles, a and a, that are in equilibrium, the frequency of the allele a is 0. 3. What i

zavuch27 [327]

Here, given-

homozygous alleles 'a' have a frequency of 0.3.

Also the alleles are in equilibrium in a Hardy-Weinberg population. The frequency of individuals that are homozygous for this allele are= 0.49.

The Hardy-Weinberg equilibrium can be defined as the principle which states that the variation in the genetic makeup of a population remains constant and unchanged till there are no external interferences, influencing the population.

Calculation-

$p + q = 1\\0.3 + q= 1\\q= 1- 0.3\\\\q= 0.7$

Then to find the frequency of the individuals homozygous for this allele the following formula needs to be used-

$p^{2} + 2pq + q^{2} =1$

$p^{2} = dominant homozygous frequency\\2pq= heterozygous frequency\\q^{2} = recessive homozygous frequency\\$

Thus, the individuals homozygous for the allele can be calculated by $q^{2} = (0.7)^{2} \\= 0.49$

Learn more about the Hardy-Weinberg equilibrium here-

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4 0

2 years ago

Why wouldnt there be any fresh water if water couldnt evaporate

Mariana [72]

You have to think of contaminated water if it were to evaporate it can effect the water cycle of an environment

8 0

3 years ago