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2 years ago

Simplify (x+y)(x-y)(x^2+y^2)

Mathematics

1 answer:

Marianna [84]2 years ago

3 0

Answer:

x⁴-y⁴

Step-by-step explanation:

=(x+y)(x-y)(x²+y²)

=(x²-y²)(x²+y²)

=x⁴-y⁴

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Direct variation. Have a nice day!

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Which of the following statements are true about the function y = 3x?

dolphi86 [110]

Answer:

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2 years ago

Complete the tables of values.

Vladimir [108]

Answer:

$a=1\\b=\frac{1}{16}\\\\c=\frac{1}{256}\\\\d=1\\e=\frac{4}{9}\\\\f=\frac{16}{81}$

Step-by-step explanation:

For the orange table:

Substitute the corresponding values of x into the function $f(x)=4^{-x}$ , then:

For a:

x=0

$f(0)=4^0=1$

For b:

x=2

$f(x)=4^{-2}=\frac{1}{16}$

For c:

x=4

$f(x)=4^{-4}=\frac{1}{256}$

For the blue table:

Substitute the corresponding values of x into the function $g(x)=(\frac{2}{3})^x$ , then:

For d:

x=0

$g(x)=(\frac{2}{3})^0=1$

For e:

x=2

$g(x)=(\frac{2}{3})^2=\frac{4}{9}$

For f:

x=4

$g(x)=(\frac{2}{3})^4=\frac{16}{81}$

3 0

2 years ago

What is the value of x in 2(5x) = 14?

Ray Of Light [21]

Answer:

x= 7/5

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Given that f(–2.4) = -1 and f(-1.9) = -8, approximate f'(-2.4). f'(-2.4)

lora16 [44]

Answer:

f'(-2.4) ≈ -14

General Formulas and Concepts:
Algebra I

Coordinate Planes

Coordinates (x, y)

Slope Formula: $\displaystyle m = \frac{y_2 - y_1}{x_2 - x_1}$

Functions

Function Notation

Calculus

Differentiation

Derivatives
Derivative Notation

Step-by-step explanation:

*Note:

The definition of a derivative is the slope of the tangent line.

Step 1: Define

Identify.

f(-2.4) = -1

f(-1.9) = -8

Step 2: Differentiate

Simply plug in the 2 coordinates into the slope formula to find slope m.

[Derivative] Set up [Slope Formula]: $\displaystyle f'(-2.4) \approx \frac{f(x_2) - f(x_1)}{x_2 - x_1}$
Substitute in coordinates: $\displaystyle f'(-2.4) \approx \frac{-8 - -1}{-1.9 - -2.4}$
Evaluate: $\displaystyle f'(-2.4) \approx -14$

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Learn more about derivatives: brainly.com/question/17830594

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Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Differentiation

6 0

2 years ago