Answer:
A) 0.303
The probability that a randomly selected student from the class has brown eyes , given they are male

Step-by-step explanation:
<u>Explanation</u>:-
Given data 
                       Brown           Blue           Hazel           Green
Females           13                  4                  6                   9          
Males                10                  2                 9                   12
<em>Let 'B' be the event of brown eyes </em>
<em>Total number of males n(M) = 33</em>
Let B/M be the event of randomly selected student from the class has brown eyes given they are male
<em>The probability that a randomly selected student from the class has brown eyes , given they are male</em>
<em></em> <em></em>
<em></em>
<em>From table the brown eyes from males = 10</em>


<u>Final answer</u>:-
The probability that a randomly selected student from the class has brown eyes , given they are male

 
        
             
        
        
        
Answer:
(3×3)+2=11
$11
Step-by-step explanation:
 
        
             
        
        
        
Answer:1/9(x+0.1)
Step-by-step explanation:
  1/9x+10/9
=1/9(x+0.1)
 
        
             
        
        
        
Answer:
16
Step-by-step explanation:
You have: 14 / (7/8)
To divide by fractions, all you have to do is take the reciprocal of the second number, aka flip it
so, if you do that, you get 14 * 8/7
14*8=112, and 112/7 is 16
 
        
                    
             
        
        
        
9514 1404 393
Answer:
   P(F|A) = 35%
Step-by-step explanation:
P(F|A) = P(F&A)/P(A) = 7%/20% = 0.35
P(F|A) = 35%
_____
The given numbers will let you fill in a table for all of the categories of workers. However, it turns out this question can be answered using only the numbers given in the problem statement.