Answer:
Absolute minimum = 7
Step-by-step explanation:
We are given graph of f'(x). f(0)=7
We need to find the absolute minimum value of f(x) over interval [-3,0]
First we will see the graph of f'(x) over interval [-3.0]
f'(-3)=3
f'(0)=0
Thus, f'(x) is decreasing
x=0 is critical point of the function f(x) because f'(0)=0
We will get absolute maximum/minimum at x=0. f(x) >0
Hence, f(0) is absolute minimum at x=0 , Absolute minimum = 7
Just divide 130 by 10 to get 13, so the answer is 13!
Answer:
Step-by-step explanation:
If diameter is 6 then the radius is half of that or 3.
A = pi * r^2
A = pi * 3^2
A = 9pi ft^2
For these lines, let
.
And for these, let
.
Now,
The vertices of
in the x-y plane are (0, 2), (2/3, 10/3), (2, 2), and (4/3, 2/3). Applying
to each of these yields, respectively, (2, 2), (2, 4), (-2, 4), and (-2, 2), which are the vertices of a rectangle whose sides are parallel to the u-v plane.
1000ft > 300 yd
1ft=3yd
1000ft=333.33yd
