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3 years ago

Please answer as fast as possible thanks

Mathematics

1 answer:

svp [43]3 years ago

3 0

The correct answer is the 2nd choice because -1/6 is closer to 0 and the surface of the pool would be considered 0. -4/6 is farther away from 0 so it is less.

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4vir4ik [10]

The third answer would be correct. TUWV ~ DEFG; 6:4.5

This is because 6 is dilated to 4.5.

Hope this helped!

8 0

3 years ago

6z + 4z and 10 +2z plssss

Ksivusya [100]

Answer:

I'm pretty sure it's 10z and 12z

you add

8 0

3 years ago

Read 2 more answers

Pls can someone help me and have it right

dangina [55]

Answer:

Problem 1:

a. x=2

b. x=3

c. x=1

Problem 2:

A multiplication equation to hold the table true:

$18\times3=54$

A division equation to hold the table true:

$\frac{54}{3} =18$

Step-by-step explanation:

Given in problem 1:

(a). The equation is $\frac{x}{6} > 1$

It holds true for all values of $x> 6$ .

Let us say $x=12$ ,

$\frac{x}{6}=\frac{12}{6} =2$ which is greater than 1.

(b). The equation is $\frac{x}{6} < 1$

It holds true for all values of $x< 6$ .

Let us say $x=3$

$\frac{x}{6} =\frac{3}{6} =\frac{1}{2}$ which is less than 1.

(c). The equation is $\frac{x}{6} = 1$

It holds true for only $x= 6$ .

Let us say $x=6$ ,

$\frac{x}{6} =\frac{6}{6}=1$ which is equal to 1.

Problem 2:

A multiplication equation to hold the table true:

$18\times3=54$

A division equation to hold the table true:

$\frac{54}{3} =18$

Therefore these are the values which hold true to the equation in problem 1 and 2.

8 0

3 years ago

Can you help me with this plz

Salsk061 [2.6K]

Hello there

Please check attached image for answer.

Hope it helps ...

~ Benjemin360

3 0

3 years ago

2x = x +3 Help pls I can’t do this one

Fudgin [204]

Answer:

x=3

Step-by-step explanation:

Subract the x from the left side and add it to the right side and then you got your answer

3 0

3 years ago