A. X is the number of years after 2000
2006-200 = 6 years.
Replace x with 6 and solve:
105(6)^2 + 680(6) + 4296 = 12,156
Answer for part a: 12,156
Answer for part B.
There was just over 12,000 in 6 years , to get to 21,500 would be a little over 9,000 more 9/12 = 0.75
6 years x .75 = 4.5 years
6 + 4.5 = 10.5 years round to 10 years for estimating purposes
Answer for part b: about 10 years
Answer:
(7 x + 6 y)^2
Step-by-step explanation:
Factor the following:
49 x^2 + 84 x y + 36 y^2
The coefficient of x^2 is 49 and the coefficient of y^2 is 36. The product of 49 and 36 is 1764. The factors of 1764 which sum to 84 are 42 and 42. So 49 x^2 + 84 x y + 36 y^2 = 49 x^2 + 42 x y + 42 x y + 36 y^2 = 7 x (7 x + 6 y) + 6 y (7 x + 6 y):
7 x (7 x + 6 y) + 6 y (7 x + 6 y)
Factor 7 x + 6 y from 7 x (7 x + 6 y) + 6 y (7 x + 6 y):
(7 x + 6 y) (7 x + 6 y)
(7 x + 6 y) (7 x + 6 y) = (7 x + 6 y)^2:
Answer: (7 x + 6 y)^2
Answer:
20
Step-by-step explanation:
40 - 15 = 25
25/1.25=20
So c-9 is less than or equal to 20 so c is less than or equal to 29. So the correct answer is c. Hope this helps :)
