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Ainat [17]
3 years ago
9

Which of the following graphs of exponential functions corresponds to a geometric sequence with a first term of 4 and a ratio of

1/2?

Mathematics
2 answers:
bogdanovich [222]3 years ago
6 0
"Graph E" is the one among the following choices given in the question that graphs <span>of exponential functions corresponds to a geometric sequence with a first term of 4 and a ratio of 1/2. The correct option among all the options that are given is the fifth option. I hope the answer has actually come to your help.</span>
ser-zykov [4K]3 years ago
3 0

Answer: graph E.


A geometric sequence can be written as:

a_{n} = a_{1} \cdot r^{(n - 1)}

where:

a₁ = first term = 4

r = ratio = 0.5


Substituting the numbers, we have:

a_{n} = 4 \cdot (\frac{1}{2})^{n-1}

or else

f(x) = 4 \cdot (\frac{1}{2})^{x - 1}


This is an exponential function with base less than 1. Therefore, we can exclude graph C (which depicts a linear function), and graphs A and D (which depict an exponential function with base greater than 1).


In order to choose between graph B and E, let's evaluate the function in two different points:

f(1) = 4 \cdot (\frac{1}{2})^{1 - 1} = 4

f(2) = 4 \cdot (\frac{1}{2})^{2 - 1} = 4 \cdot \frac{1}{2} = 2


Therefore, we need to look for the graph passing through the points (1, 4) and (2, 2). That is graph E.




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NeTakaya

Answ

Step-by-step explanation:

Two point slope =-(-6+6)/(6-2) =0

Equation is y+6 = 0(x-2)

y+6=0

y=-6

The point is -6 at y axis which is a horizontal line.

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3 years ago
Given: AACD is isosceles with angle D as the vertex angle. B is the midpoint of AC. AB= x + 5, BC= 2x - 3, and CD = 2x + 6. Find
Marina86 [1]

Answer:

  • 70 units

Step-by-step explanation:

<u>Given triangle ACD</u>

  • AB = BC
  • CD = 2x + 6
  • AB = x + 5
  • BC = 2x - 3
  • P = ?

<u>Perimeter is sum of the side lengths:</u>

  • P = AD + CD + AC

AD = CD because D is vertex and the triangle is isosceles

AC = AB + BC because B is midpoint of AC

<u>Then P is:</u>

  • P = 2(2x + 6) + (x + 5) + (2x -3) = 4x + 12 + x + 5 + 2x - 3 = 7x + 14

<u>Find the value of x from the AB = BC:</u>

  • x + 5 = 2x - 3
  • 2x - x = 5 + 3
  • x = 8

<u>Then find the value of P:</u>

  • P = 7*8 + 14 = 56 + 14 = 70 units

3 0
3 years ago
Factorise ab+cb+ad+cd ​
shutvik [7]

Answer:

ab=a×b

cb=c×b

ad=a×d

cd=c×d

4 0
3 years ago
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Imagine that you have entered the following distribution of scores into the program: 7, 9, 6, 3, 7, 8, 4, 10, 7, 9. The mean of
ozzi

Answer:

3

Step-by-step explanation:

Mean refers to the average value of the set of data.

It is the central value of the set of data.

Another word for Mean is average.

Given scores:7, 9, 6, 3, 7, 8, 4, 10, 7, 9

Solution:

Sum of observations = 7+ 9+ 6+ 3+ 7+ 8+ 4+ 10+ 7+ 9=70

Number of observations = 10

Mean = Sum of observations/Number of observations = \frac{70}{10}=7

If observation 3 is removed:

Sum of observations = 7+ 9+ 6+  7+ 8+ 4+ 10+ 7+ 9=67

Number of observations = 9

Mean =  Sum of observations/Number of observations = \frac{67}{9}=7.44

If observation 4 is removed:

Sum of observations = 7+ 9+ 6+ 3+ 7+ 8+ 10+ 7+ 9=66

Number of observations = 9

Mean = \frac{66}{9}=7.3

If observation 6 is removed:

Sum of observations = 7+ 9+ 3+ 7+ 8+ 4+ 10+ 7+ 9=64

Number of observations = 9

Mean = \frac{64}{9}=7.1

If observation 7 is removed:

Sum of observations = 9+ 6+ 3+  8+ 4+ 10+  9=49

Number of observations = 7

Mean = \frac{49}{7}=7

If observation 8 is removed:

Sum of observations = 7+ 9+ 6+ 3+ 7+  4+ 10+ 7+ 9=62

Number of observations = 9

Mean = \frac{62}{9}=6.9

If observation 9 is removed:

Sum of observations = 7+ 6+ 3+ 7+ 8+ 4+ 10+ 7=52

Number of observations = 8

Mean = \frac{52}{8}=6.5

If observation 10 is removed:

Sum of observations = 7+ 9+ 6+ 3+ 7+ 8+ 4+ 7+ 9=60

Number of observations = 9

Mean = \frac{60}{9}=6.7

Therefore, mean of this distribution of scores would be changed the most if a score 3 was removed from the data set.

6 0
4 years ago
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stellarik [79]

Answer:

For number 9)

Interval notation (-\infty,3]

For number 10)

Interval notation: (-\infty,\frac{-1}{2}) \cup (\frac{-1}{2},\infty).

Step-by-step explanation:

On square roots you have to make sure the inside is positive or zero.

So the domain of the first one will come from solving

6-2x \ge 0

Subtract 6 on both sides:

-2x \ge -6

Divide both sides by -2 (flip inequality when divide both sides by negative):

x \le 3

The domain is less than or equal to 3.

Interval notation (-\infty,3]

On fractions you have to watch out for dividing by 0.

The domain is all real numbers except when 4x+2=0.

4x+2=0

Subtract 2 on both sides:

4x=-2

Divide both sides by 4:

x=-2/4

Reduce:

x=-1/2

The domain is all real numbers except when x=-1/2

Interval notation: (-\infty,\frac{-1}{2}) \cup (\frac{-1}{2},\infty).

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4 years ago
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