Answer:
The volume of the tumor experimented a decrease of 54.34 percent.
Step-by-step explanation:
Let suppose that tumor has an spherical geometry, whose volume (
) is calculated by:

Where
is the radius of the tumor.
The percentage decrease in the volume of the tumor (
) is expressed by:

Where:
- Absolute decrease in the volume of the tumor.
- Initial volume of the tumor.
The absolute decrease in the volume of the tumor is:


The percentage decrease is finally simplified:
![\%V = \left[1-\left(\frac{R_{f}}{R_{o}}\right)^{3} \right]\times 100\,\%](https://tex.z-dn.net/?f=%5C%25V%20%3D%20%5Cleft%5B1-%5Cleft%28%5Cfrac%7BR_%7Bf%7D%7D%7BR_%7Bo%7D%7D%5Cright%29%5E%7B3%7D%20%5Cright%5D%5Ctimes%20100%5C%2C%5C%25)
Given that
and
, the percentage decrease in the volume of tumor is:
![\%V = \left[1-\left(\frac{0.77\cdot R}{R}\right)^{3} \right]\times 100\,\%](https://tex.z-dn.net/?f=%5C%25V%20%3D%20%5Cleft%5B1-%5Cleft%28%5Cfrac%7B0.77%5Ccdot%20R%7D%7BR%7D%5Cright%29%5E%7B3%7D%20%5Cright%5D%5Ctimes%20100%5C%2C%5C%25)

The volume of the tumor experimented a decrease of 54.34 percent.
Step-by-step explanation:


* open dot
You did not provide the graphs to choose from so use the table above to determine which graph fits those coordinates.
Make sure that:
- (0, -3) has an open dot
- nothing is plotted between x = 0 and x = 2
- (2, -4) has a closed dot
Answer:
BC = 7.
Step-by-step explanation:
subtract 12 inches from 19 and then you get the result for BC.
Answer:
y = -2x + 16.
Step-by-step explanation:
The slope of the perpendicular line = -1 / slope of the given line
= -1 / 1/2 = -2.
Using the point slope form of the equation of a straight line:
y - y1 = m (x - x1)
y - 8 = -2(x - 4)
y - 8 = -2x + 8
y = -2x + 16 is the required equation.
Answer:
4th answer aka the last one
Step-by-step explanation: