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3 years ago

What sport has the largest gender difference in terms of preference

Mathematics

1 answer:

vazorg [7]3 years ago

5 0

Football because only guys play it proffesionally

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In a normal bell shaped curve, approximately which percentage of scores fall within 3 standard deviation (-3 to +3) or blank (34

Leokris [45]

Let x represent the scores. With mean and standard deviation given,

The Empirical rule states that

1) About 68% of the x values lie between 1 standard deviation below and above the mean

2) About 95% of the x values lie between 2 standard deviation below and above the mean

3) About 99.7% of the x values lie between 3 standard deviation below and above the mean

If we consider this rule, then the percentage of scores that fall within 3 standard deviation (-3 to +3) is 99% because this is closer to 99.7%

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8 months ago

Explain the difference between evaluating 3 * 7 - 4 ÷ 2 and evaluating 3(7 - 4) ÷ 2.

Bogdan [553]

DIY. I believe in you, its just a matter if you believe in yourself. Your welcome

6 0

2 years ago

Read 2 more answers

Cecil started from point A and moved according to the expression 8+(-5)+7+6+(-7)+5+(-8).What one additional step does Cecil need

cupoosta [38]

Im pretty sure that i can solve this for ya

6 0

2 years ago

Read 2 more answers

Help pleaseeeeeeeeeeeeeeeeeeeeeee

bixtya [17]

Answer: $\bold{(1)\ \dfrac{19,683}{64}\qquad (2)\ 16}$

<u>Step-by-step explanation:</u>

(1) (12, 18, 27, ...)

The common ratio is:

$r=\dfrac{a_{n+1}}{a_n}\quad r =\dfrac{18}{12}=\boxed{\dfrac{3}{2}}\quad \rightarrow \quad r=\dfrac{27}{18}=\boxed{\dfrac{3}{2}}$

The equation is:

$a_n=a_o(r)^{n-1}\\\\Given:a_o=12,\ r=\dfrac{3}{2}\\\\\\Equation:\\a_n =12\bigg(\dfrac{3}{2}\bigg)^{n-1}\\\\\\\\9th\ term:\\a_9=12\bigg(\dfrac{3}{2}\bigg)^{9-1}\\\\\\a_9=12\bigg(\dfrac{3}{2}\bigg)^{8}\\\\\\.\quad =\large\boxed{\dfrac{19643}{64}}$

$(2)\qquad \bigg(\dfrac{1}{16},\dfrac{1}{8},\dfrac{1}{4},\dfrac{1}{2}\bigg)\\\\\\\text{The common ratio is}:\\\\r=\dfrac{a_{n+1}}{a_n}\quad r=\dfrac{\frac{1}{8}}{\frac{1}{16}}=\boxed{2}\quad \rightarrow \quad r=\dfrac{\frac{1}{4}}{\frac{1}{8}}=\boxed{2}$

The equation is:

$a_n=a_o(r)^{n-1}\\\\Given:a_o=\dfrac{1}{16},\ r=2\\\\\\Equation:\\a_n =\dfrac{1}{16}(2)^{n-1}\\\\\\\\9th\ term:\\a_9=\dfrac{1}{16}(2)^{9-1}\\\\\\a_9=\dfrac{1}{16}(2)^{8}\\\\\\.\quad =\large\boxed{16}$

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2 years ago

Please help!! (math)

olga55 [171]

Bro answer.

Step-by-step explanation:

This is the step of doing this so write this in class 10 we do like this ok

7 0

1 year ago