Question

LK is tangent to circle J at point K. What is the length of the radius? 6/25 85/12 121/36 157/12

Answer 1

Answer:

85/12

Step-by-step explanation:

Answer 2

Answer:

The answer is indeed, 85/12 ; B

Using the Pythagorean theorem, you can use FOIL to solve for the hypotenuse then subtract the radius from the entire hypotenuse to find R. Since all radii are congruent.

$11^2 + r^2 = (6+r)^2\\11^2 + r^2 = (6+r) (6+r)\\121 + r^2 = 36 + 6r + 6r + r^2\\121 + r^2 = 36 + 12r + r^2$

Simplify the rest. We also know that (6+r)^2 is the hypotenuse since angle JKL is a right angle as it is perpendicular to the center and is a tangent.