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Gala2k [10]
3 years ago
13

LK is tangent to circle J at point K. What is the length of the radius? 6/25 85/12 121/36 157/12

Mathematics
2 answers:
schepotkina [342]3 years ago
4 0

Answer:

85/12

Step-by-step explanation:

hammer [34]3 years ago
3 0

Answer:

The answer is indeed, 85/12 ; B

Using the Pythagorean theorem, you can use FOIL to solve for the hypotenuse then subtract the radius from the entire hypotenuse to find R. Since all radii are congruent.

11^2 + r^2 = (6+r)^2\\11^2 + r^2 = (6+r) (6+r)\\121 + r^2 = 36 + 6r + 6r + r^2\\121 + r^2 = 36 + 12r + r^2\\

Simplify the rest. We also know that (6+r)^2 is the hypotenuse since angle JKL is a right angle as it is perpendicular to the center and is a tangent.

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On a coordinate plane, point A is located at (7, 4), and point B is located at (-8, 4). What is the distance between the two poi
wel

Answer:

Solution given;

A(x1,y1)=(7,4)

B(x2,y2)=(-8,4)

distance AB=?

we have

d=\sqrt{(x2-x1) ²+(y2-y1) ²}

AB=\sqrt{(-8-7)²+(4-4)²}

AB=15 units

the distance between the two points is 15 units.

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2 years ago
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sergiy2304 [10]

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8 0
2 years ago
(ASAP PICTURE ADDED) What is the simplified form of the following expression?
bonufazy [111]

Answer:

option c is correct.

Step-by-step explanation:

7\left(\sqrt[3]{2x}\right)-3\left(\sqrt[3]{16x}\right)-3\left(\sqrt[3]{8x}\right)

WE need to simplify this equation.

Solve the parenthesis of each term.

=7\left\sqrt[3]{2x}\right-3\left\sqrt[3]{16x}\right-3\left\sqrt[3]{8x}\right

Now, We will find factors of the terms inside the square root

factors of 2: 2

factors of 16 : 2x2x2x2

factors of 8: 2x2x2

Putting these values in our equation:=7\left(\sqrt[3]{2x}\right)-3\left(\sqrt[3]{2X2X2X2 x}\right)-3\left(\sqrt[3]{2X2X2 x}\right)\\=7\left(\sqrt[3]{2x}\right)-3\left(\sqrt[3]{2X2X2} \sqrt[3] {2 x}\right)-3\left(\sqrt[3]{2X2X2} \sqrt[3]{x}\right)\\=7\left(\sqrt[3]{2x}\right)-3\left(\sqrt[3]{2^3} \sqrt[3] {2 x}\right)-3\left(\sqrt[3]{2^3} \sqrt[3]{x}\right)\\=7\left(\sqrt[3]{2x}\right)-3*2\left(\sqrt[3] {2 x}\right)-3*2\left(\sqrt[3]{x}\right)\\=7\left(\sqrt[3]{2}\sqrt[3]{x}\right)-6\left(\sqrt[3] {2}\sqrt[3]{x})-6\left(\sqrt[3]{x}\right)

Adding like terms we get:

=7\left(\sqrt[3]{2}\sqrt[3]{x}\right)-6\left(\sqrt[3] {2}\sqrt[3]{x})-6\left(\sqrt[3]{x}\right\\=(\sqrt[3] {2}\sqrt[3]{x})-6\left(\sqrt[3]{x}\right)\\

(\sqrt[3] {2}\sqrt[3]{x})-6\left(\sqrt[3]{x}\right)\\can\,\,be \,\, written\,\, as\,\,\\(\sqrt[3] {2x})-6\left(\sqrt[3]{x}\right)

So, option c is correct

5 0
3 years ago
Read 2 more answers
Which constant could each equation be multiplied by to eliminate the x variable in this system of equations? 4x + 5y = 62 5x − 3
qwelly [4]

Answer:

Multiply equation 4x+5y=62 by 5 and 5x-3y=22 by 4

Step-by-step explanation:

Given:

Equations are 4x+5y=62,5x-3y=22

To find: constant by which each equation should be multiplied to eliminate the variable x in the given system of equations

Solution:

4x+5y=62...(i)\\5x-3y=22...(ii)

Multiply equation (i) by 5 and (ii) by 4 to get the following equations:

20x+25y=310\\20x-12y=88

On subtracting these equations, we get

(20x+25y)-(20x-12y)=310-88\\\\13y=222

So, the variable x gets eliminated

7 0
3 years ago
What is the y intercept of y= -3x
tatuchka [14]

Answer:

(0,0)

Step-by-step explanation:

y= -3x

The y intercept is the y value when x =0

Let x =0

y = -3(0)

y = 0

(0,0)

3 0
3 years ago
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