Pls help!!! only 20 minutes left pls help 100 point math question

Find the p-value: An independent random sample is selected from an approximately normal population with an unknown standard devi

vladimir1956 [14]

Answer:

(a) p-value = 0.043. Null hypothesis is rejected.

(b) p-value = 0.001. Null hypothesis is rejected.

(c) p-value = 0.444. Null hypothesis is not rejected.

(d) p-value = 0.022. Null hypothesis is rejected.

Step-by-step explanation:

To test for the significance of the population mean from a Normal population with unknown population standard deviation a t-test for single mean is used.

The significance level for the test is α = 0.05.

The decision rule is:

If the p - value is less than the significance level then the null hypothesis will be rejected. And if the p-value is more than the value of α then the null hypothesis will not be rejected.

(a)

The alternate hypothesis is:

Hₐ: μ > μ₀

The sample size is, n = 11.

The test statistic value is, t = 1.91 ≈ 1.90.

The degrees of freedom is, (n - 1) = 11 - 1 = 10.

Use a t-table t compute the p-value.

For the test statistic value of 1.90 and degrees of freedom 10 the p-value is:

The p-value is:

P (t₁₀ > 1.91) = 0.043.

The p-value = 0.043 < α = 0.05.

The null hypothesis is rejected at 5% level of significance.

(b)

The alternate hypothesis is:

Hₐ: μ < μ₀

The sample size is, n = 17.

The test statistic value is, t = -3.45 ≈ 3.50.

The degrees of freedom is, (n - 1) = 17 - 1 = 16.

Use a t-table t compute the p-value.

For the test statistic value of -3.50 and degrees of freedom 16 the p-value is:

The p-value is:

P (t₁₆ < -3.50) = P (t₁₆ > 3.50) = 0.001.

The p-value = 0.001 < α = 0.05.

The null hypothesis is rejected at 5% level of significance.

(c)

The alternate hypothesis is:

Hₐ: μ ≠ μ₀

The sample size is, n = 7.

The test statistic value is, t = 0.83 ≈ 0.82.

The degrees of freedom is, (n - 1) = 7 - 1 = 6.

Use a t-table t compute the p-value.

For the test statistic value of 0.82 and degrees of freedom 6 the p-value is:

The p-value is:

P (t₆ < -0.82) + P (t₆ > 0.82) = 2 P (t₆ > 0.82) = 0.444.

The p-value = 0.444 > α = 0.05.

The null hypothesis is not rejected at 5% level of significance.

(d)

The alternate hypothesis is:

Hₐ: μ > μ₀

The sample size is, n = 28.

The test statistic value is, t = 2.13 ≈ 2.12.

The degrees of freedom is, (n - 1) = 28 - 1 = 27.

Use a t-table t compute the p-value.

For the test statistic value of 0.82 and degrees of freedom 6 the p-value is:

The p-value is:

P (t₂₇ > 2.12) = 0.022.

The p-value = 0.444 > α = 0.05.

The null hypothesis is rejected at 5% level of significance.

5 0

3 years ago

Emily biked 9 miles in 3/4 hour. Which expression can she use to find her unit rate in miles per hour?

frosja888 [35]

The expression will be 9 x 3/4

7 0

3 years ago

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A rectangular floor space in a community center is 40 ft long and 32 ft wide. A volunteer is setting up chairs on the floor spac

pav-90 [236]

It is B because 40x32=1280 and 5x4=20 then divide 1280 by 20 and you get 64 but you can’t have 64 so you would need to only have 60 so the answer is B

6 0

3 years ago

The graph shows the prices, in dollars, of different numbers of pies at Erik's store. The table shows the prices, in dollars, of

expeople1 [14]

Answer:

Step-by-step explanation:

The graph shows the prices, in dollars, of different numbers of pies at Erik's store. The table shows the prices, in dollars, of different numbers of doughnuts at the same store. A graph shows Number of Pies on x-axis and Price of Pies on y-axis. The x-axis scale is shown from 0 to 12 at increments of 2, and the y-axis scale is shown from 0 to 160 at increments of 20. A straight line joins the ordered pairs 2, 20 and 4, 40 and 6, 60 and 8, 80 and 10, 100 and 12, 120. Doughnuts Number of Doughnuts Price of Doughnuts (dollars) 2 6 4 12 6 18 8 24 How many dollars more is the price of a pie than the =doughnut at Erik's store? $2 $3 $6 $7The graph shows the prices, in dollars, of different numbers of pies at Erik's store. The table shows the prices, in dollars, of different numbers of doughnuts at the same store. A graph shows Number of Pies on x-axis and Price of Pies on y-axis. The x-axis scale is shown from 0 to 12 at increments of 2, and the y-axis scale is shown from 0 to 160 at increments of 20. A straight line joins the ordered pdoughnut at Erik's store? $2 $3 $6 $7The graph shows the prices, in dollars, of different numbers of pies at Erik's store. The table shows the prices, in dollars, of different numbers of doughnuts at the same store. A graph shows Number of Pies on x-axis and Price of Pies on y-axis. The x-axis scale is shown from 0 to 12 at increments of 2, and the y-axis scale is shown from 0 to 160 at increments of 20. A straight line joins the ordered pairs 2, 20 and 4, 40 and 6, 60 and 8, 80 and 10, 100 and 12, 120. Doughnuts Number of Doughnuts Price of Doughnuts (dollars) 2 6 4 12 6 18 8 24 How many dollars more is the price of a pie than the price of a doughnut at Erik's store? $2 $3 $6 $7The graph shows the prices, in dollars, of different numbers of pies at Erik's store. The table shows the prices, in dollars, of different numbers of doughnuts at the same store. A graph shows Number of Pies on x-axis and Price of Pies on y-axis. The x-axis scale is shown from 0 to 12 at increments of 2, and the y-axis scale is shown from 0 to 160 at increments of 20. A straight line joins the ordered pairs 2, 20 and 4, 40 and 6, 60 and 8, 80 and 10, 100 and 12, 120. Doughnuts Number of Doughnuts Price of Doughnuts (dollars) 2 6 4 12 6 18 8 24 How ma=

8 0

2 years ago

Find an equation of a line passing through the point (8,9) and parallel to the line joining the points (2,7) and (1,5).

TiliK225 [7]

Answer:

2x - y - 7 = 0

Step-by-step explanation:

Since the slope of parallel line are same.

So, we can easily use formula,

y - y₁ = m ( x ₋ x₁)

where, (x₁, y₁) = (8, 9)

and m is a slope of line passing through (x₁, y₁).

and since the slope of parallel lines are same, so here we use slope of parallel line for calculation.

and, Slope = m = $\dfrac{y_{b}-y_{a}}{x_{b}-x_{a}}$

here, (xₐ, yₐ) = (2, 7)

and, $(y_{a},y_{b}) = (1, 5 )$

⇒ m = $\dfrac{5-7}{1-2}$

⇒ m = 2

Putting all values above formula. We get,

y - 9 = 2 ( x ₋ 8)

⇒ y - 9 = 2x - 16

⇒ 2x - y - 7 = 0

which is required equation.

3 0

3 years ago

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