Answer: 1) D 2) B
<u>Step-by-step explanation:</u>
1) The denominator cannot equal zero, Factor the denominator to find the zeros. n³ - 4n² + 3n = 0
n(n - 3)(n - 1) = 0
n=0 n-3=0 n-1=0
n=0 n=3 n=1
2) In order to be a rational expression, it must be in the form
where both a and b are integers.
Since ![\sqrtb](https://tex.z-dn.net/?f=%5Csqrtb)
is irrational and not an integer, then the expressions containing an irrational term <em>after simplified</em> cannot result in an integer.
Therefore, options <em>(i)</em> and <em>(iv)</em> are not rational expressions.
Option <em>(iii)</em> contains b as an exponent. Since there is no information about b, it could be a fraction, which means it could be an irrational number.
Answer:
$15.27
Step-by-step explanation:
Answer:
24
Step-by-step explanation:
= 49 because any number squared is positive.
Since b=2,
2(-4)= -8.
Then this is 49-8-17, which equals 24.
I think it might be c, or a.
Hey!
Finding the factorial for the first few numbers, we have:
1!=1
2!=2
3!=6
4!=24
5!=120
6!=720
7!=720*7
8!=720*56
What we can see as a clear pattern from 5! and on is that our number ends with a 0, making the units digit 0. Therefore, when we add the units digit of 5! and on, we have a result of 0. So, we can simply add the units digits of 1!, 2!, 3!, and 4!, which is 1+2+6+4=13. Since the units digit is the last number, we can drop the tens place to get an answer of 3.
Feel free to ask further questions!