1. First, let us define the width of the rectangle as w and the length as l.
2. Now, given that the length of the rectangle is 6 in. more than the width, we can write this out as:
l = w + 6
3. The formula for the perimeter of a rectangle is P = 2w + 2l. We know that the perimeter of the rectangle in the problem is 24 in. so we can rewrite this as:
24 = 2w + 2l
4. Given that we know that l = w + 6, we can substitute this into the formula for the perimeter above so that we will have only one variable to solve for. Thus:
24 = 2w + 2l
if l = w + 6, then: 24 = 2w + 2(w + 6)
24 = 2w + 2w + 12 (Expand 2(w + 6) )
24 = 4w + 12
12 = 4w (Subtract 12 from each side)
w = 12/4 (Divide each side by 4)
w = 3 in.
5. Now that we know that the width is 3 in., we can substitute this into our formula for length that we found in 2. :
l = w + 6
l = 3 + 6
l = 9 in.
6. Therefor the rectangle has a width of 3 in. and a length of 9 in.
Answer: C and for the bottom is 3*3/8=9/8=1 1/8
Step-by-step explanation: hoped this helped :)
(3,4)(2,-1)
slope(m) = (y2 - y1) / (x2 - x1)
slope(m) = (-1-4) / (2 - 3) = -5/-1 = 5
y = mx + b
slope(m) = 5
u can use either of ur points...(3,4)...x = 3 and y = 4
now we sub and find b, the y int
4 = 5(3) + b
4 = 15 + b
4 - 15 = b
- 11 = b
so ur equation is : y = 5x - 11 <===
Answer: One 8-cm pipe (Its is greater than the total area of of two 4-cm pipes)
Step-by-step explanation:
The area of a circle can be calculate with this formula:
Where "r" is the radius of the circle.
We need to calculate the area of 8-cm pipe. In this case:
Then, substituting the radius into the formula, we get:
Now we must calculate the area of the two 4-cm pipes.
Since they are two pipes, the formula is:
In this case:
Then, substituting into the formula, we get:
Therefore, since the area of one 8-cm pipe is greater than the total area of of two 4-cm pipes, we conclude that the pipe configuration that can deliver more water to residents is:
One 8-cm pipe
An expression that is equivalent to ![\sqrt[5]{13^3}](https://tex.z-dn.net/?f=%20%5Csqrt%5B5%5D%7B13%5E3%7D%20%20)
is 
