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Ivenika [448]
3 years ago
12

If two lines having equations 3x+5y-16=0 and 4y-mx= 20 are parallel, find the value of m

Mathematics
1 answer:
sergejj [24]3 years ago
3 0

Answer:

m = -3/5

Step-by-step explanation:

since both lines are given as "parallel", they will have the same slope, so we only need to solve for one.

we will put this equation into slope-intercept form to find the slope

3x + 5y - 16 = 0

3x + 5y = 16

5y = -3x + 16

y = -3/5x + 16/5

m = -3/5

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‼️GEOMETRY‼️
ella [17]

Answer:

A.) 1018 square inches

Step-by-step explanation:

The largest sphere will have a diameter equaling the length of the cube (see picture).

If the side length of the cube is 18 inches, the diameter of the sphere is also 18 inches. Use the surface area formula for a circle:

SA=4\pi r^2

For this formula, we need the radius of the sphere. Divide the diameter by 2:

\frac{18}{2}=9

The radius is 9 inches. Plug this into the equation:

SA=4\pi *9^2

Simplify the equation:

SA=4\pi *81\\\\SA=324\pi \\\\SA=1017.87

Round the result to the nearest whole number:

1017.87 → 1018

The surface area is 1,018 inches².

:Done

Picture:

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6 0
3 years ago
40% of the students in a class are girls and the number of boys is 24 find the total number of students and the number of girls​
navik [9.2K]

Answer:

Girls = 16

Total students = 40

Step-by-step explanation:

40% of the students are girls, this means 60% of the students are boys.

To find the number of girls, setup a proportion using the percentages and actual number of students in the class. I am going to make the numerator the numbers that go with the girls and the denominator will be the numbers that go with the boys.

Also let's convert the percentages to decimals by moving the decimal two places left.

40% = 0.4 and 60% = 0.6

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Now let's find the total number of students by adding the number of girls to the number of boys.

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7 0
2 years ago
Is 5 1/4 divided by 3 1/2 the same as 3 1/2 divided by 5 1/4?
sashaice [31]

Answer:

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4 0
3 years ago
Help me on this problem please?????
Y_Kistochka [10]
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3 years ago
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