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laila [671]
3 years ago
9

What is the length of a segment with endpoints at F(6, 4) and G(14, 19)? Round to the nearest whole number.

Mathematics
1 answer:
Mila [183]3 years ago
4 0

Answer:

17

Step-by-step explanation:

d = √( (x₂ - x₁)² + (y₂ - y₁)² )

   = √( (14 - 6)² + (19 - 4)² )

   = √( 8² + 15² )

   = √( 64 + 225 )

   =  \sqrt{289}

   = 17

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Step-by-step explanation:

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Answer:

Fraction: 1/256 or

Decimal: 0.00390625 or 0.00391

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4^-4=1/4^4

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Required information An article presents a new method for timing traffic signals in heavily traveled intersections. The effectiv
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Answer:

652.6-2.01\frac{311.7}{\sqrt{50}}=563.997    

652.6+2.01\frac{311.7}{\sqrt{50}}=741.203    

So on this case the 95% confidence interval would be given by (563.997;741.203)    

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X=652.6 represent the sample mean for the sample  

\mu population mean (variable of interest)

s=311.7 represent the sample standard deviation

n=50 represent the sample size  

Soltuion to the problem

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

In order to calculate the critical value t_{\alpha/2} we need to find first the degrees of freedom, given by:

df=n-1=50-1=49

Since the Confidence is 0.95 or 95%, the value of \alpha=0.05 and \alpha/2 =0.025, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.025,49)".And we see that t_{\alpha/2}=2.01

Now we have everything in order to replace into formula (1):

652.6-2.01\frac{311.7}{\sqrt{50}}=563.997    

652.6+2.01\frac{311.7}{\sqrt{50}}=741.203    

So on this case the 95% confidence interval would be given by (563.997;741.203)    

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3 years ago
Sam is on the swim team. Each week he swims a total of
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Ok so there are 1000 meters in a kilogram right so 
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