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laila [671]
3 years ago
9

What is the length of a segment with endpoints at F(6, 4) and G(14, 19)? Round to the nearest whole number.

Mathematics
1 answer:
Mila [183]3 years ago
4 0

Answer:

17

Step-by-step explanation:

d = √( (x₂ - x₁)² + (y₂ - y₁)² )

   = √( (14 - 6)² + (19 - 4)² )

   = √( 8² + 15² )

   = √( 64 + 225 )

   =  \sqrt{289}

   = 17

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Nataly_w [17]
<h3>Answer: 2 < x < 7</h3>

==================================================

Explanation:

We'll use the hinge theorem here. This says (more or less) that the larger an angle is, the side opposite of that will be longer.

Imagine that the segments with the single tickmarks represent a door swinging open/shut. The more open a door is, the further the distance it is from the handle to the frame. In terms of these triangles, the segment 25 is larger than 5x-10 because the angle 90 (opposite the 25) is larger than the angle 85 degrees (opposite the 5x-10)

In symbols we say

5x - 10 < 25

We also say 5x - 10 > 0 or 0 < 5x - 10 to ensure that the segment of length 5x-10 is not 0 or negative.

Put the two inequalities together and we get 0 < 5x - 10 < 25

------------

Solve for x

0 < 5x - 10 < 25

0+10 < 5x - 10 < 25 + 10 .... adding 10 to all sides

10 < 5x < 35

10/5 < 5x/5 < 35/5 ... dividing all sides by 5

2 < x < 7

We have x between 2 and 7, and not equal to either endpoint.

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Step-by-step explanation:

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3 years ago
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Answer:

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You set up two equations:

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