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laila [671]
3 years ago
9

What is the length of a segment with endpoints at F(6, 4) and G(14, 19)? Round to the nearest whole number.

Mathematics
1 answer:
Mila [183]3 years ago
4 0

Answer:

17

Step-by-step explanation:

d = √( (x₂ - x₁)² + (y₂ - y₁)² )

   = √( (14 - 6)² + (19 - 4)² )

   = √( 8² + 15² )

   = √( 64 + 225 )

   =  \sqrt{289}

   = 17

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Please I will rate you with 5 stars just please help me with this problem
olchik [2.2K]

Answer:

D

Step-by-step explanation:

If we isolate the variable in each given compound inequality, we can quickly realize that D is correct.

16\geq 3x+4>1\\12\geq 3x>-3\\4\geq x>-1

x is less than or equal to four (solid point on 4 with line going left), but greater than -1 (open point going right).

Signs with 'or equal to' have solid points, and signs without are not solid.

I hope this helps!

8 0
3 years ago
Dr. gavin is conducting a 2 x 4 independent-groups factorial design. how many interactions will dr. gavin need to examine?
Sholpan [36]
For the answer to the question above, I believe the answer is simply <u><em>8.
</em></u>

2 groups divided into four participants. So all in all people needed is 8.
I hope this helped you. Have a nice day!
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8 0
3 years ago
One urn contains one blue ball (labeled b1) and three red balls (labeled r1, r2, and r3). a second urn contains two red balls (r
Flura [38]

Answer:

12 possibilities

Step-by-step explanation:

In the first urn, we have 4 balls, and all of them are different, as they have different labels, so the group of two red balls r1 and r2 is different from the group of red balls r2 and r3.

The same thing occurs in the second urn, as all balls have different labels.

The problem is a combination problem (the group r1 and r2 is the same group r2 and r1).

For the first urn, we have a combination of 4 choose 2:

C(4,2) = 4!/2!*2! = 4*3*2/2*2 = 2*3 = 6 possibilities

For the second urn, we also have a combination of 4 choose 2, so 6 possibilities.

In total we have 6 + 6 = 12 possibilities.

3 0
3 years ago
Read 2 more answers
What is the value of y when x = 43<br> A. 87<br> B. 85<br> C. 49<br> D. 45
BartSMP [9]

Answer:

A x

=

3

,

−

1x

=

3

,

−

1

Step-by-step explanation:

x

=

3

,

−

1

3 0
3 years ago
Which is the simplified form of the expression ((2 Superscript negative 2 Baseline) (3 Superscript 4 Baseline)) Superscript nega
AlekseyPX

Answer:

The option "StartFraction 1 Over 3 Superscript 8" is correct

That is \frac{1}{3^8} is correct answer

Therefore [(2^{-2})(3^4)]^{-3}\times [(2^{-3})(3^2)]^2=\frac{1}{3^8}

Step-by-step explanation:

Given expression is ((2 Superscript negative 2 Baseline) (3 Superscript 4 Baseline)) Superscript negative 3 Baseline times ((2 Superscript negative 3 Baseline) (3 squared)) squared

The given expression can be written as

[(2^{-2})(3^4)]^{-3}\times [(2^{-3})(3^2)]^2

To find the simplified form of the given expression :

[(2^{-2})(3^4)]^{-3}\times [(2^{-3})(3^2)]^2

=(2^{-2})^{-3}(3^4)^{-3}\times (2^{-3})^2(3^2)^2 ( using the property (ab)^m=a^m.b^m )

=(2^6)(3^{-12})\times (2^{-6})(3^4) ( using the property (a^m)^n=a^{mn}

=(2^6)(2^{-6})(3^{-12})(3^4) ( combining the like powers )

=2^{6-6}3^{-12+4} ( using the property a^m.a^n=a^{m+n} )

=2^03^{-8}

=\frac{1}{3^8} ( using the property a^{-m}=\frac{1}{a^m} )

Therefore [(2^{-2})(3^4)]^{-3}\times [(2^{-3})(3^2)]^2=\frac{1}{3^8}

Therefore option "StartFraction 1 Over 3 Superscript 8" is correct

That is \frac{1}{3^8} is correct answer

6 0
3 years ago
Read 2 more answers
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