The answer is C it’s vertex is at (2,4) because a quadratic formula is suppose to look like y= a ( x - h )^2 + k and the vertex is (h,k) when you look back at Your question h=-2 and but Bc of the formula then it’ll be h=2 and then k=4 and that’s how you get the vertex from a quadratic formula. Hope this helps :)
Answer:
-3.5
Step-by-step explanation:
An example is -3.5.
It is 2 4/5, 2 4/5 is 2.8, 4/5 is greater than 3/4
Some basic formulas involving triangles
\ a^2 = b^2 + c^2 - 2bc \textrm{ cos } \alphaa 2 =b 2+2 + c 2
−2bc cos α
\ b^2 = a^2 + c^2 - 2ac \textrm{ cos } \betab 2=
m_b^2 = \frac{1}{4}( 2a^2 + 2c^2 - b^2 )m b2 = 41(2a 2 + 2c 2-b 2)
b
Bisector formulas
\ \frac{a}{b} = \frac{m}{n} ba =nm
\ l^2 = ab - mnl 2=ab-mm
A = \frac{1}{2}a\cdot b = \frac{1}{2}c\cdot hA=
\ A = \sqrt{p(p - a)(p - b)(p - c)}A=
p(p−a)(p−b)(p−c)
\iits whatever A = prA=pr with r we denote the radius of the triangle inscribed circle
\ A = \frac{abc}{4R}A=
4R
abc
- R is the radius of the prescribed circle
\ A = \sqrt{p(p - a)(p - b)(p - c)}A=
p(p−a)(p−b)(p−c)
