Question

Can anyone quickly solve this trig problem, thank you!

Answer 1

Answer:

Step-by-step explanation:

a) A = (28 - 14) / 2 = 7

b) T = 2(11½ - 6½) = 10

c) P = (6½ - T/4, 28 - A) = (4, 21)

d) general form y = Asin(ωx + φ) + d

  We have already found amplitude A = 7

  the upward displacement from the x axis is 21

  The portion in parenthesis will be in radians. The cycle repeats every 10 x units so ω = 2πx/10 = 0.2πx

To find φ, which is 4/10 of a cycle behind the upward tracing zero point, we subtract 2π(4/10) = 0.8π

y = 7sin(0.2πx - 0.8π) + 21

y = 7sin(π(0.2x - 0.8)) + 21

e) The easiest "difference" we can make is to change φ

Because the pattern repeats, 4/10 of a cycle backward is the same as 6/10 of a cycle forward. 6/10(2π) = 1.2π

y = 7sin(π(0.2x + 1.2)) + 21

We could also change it to a cosine function which would also change our option for φ by π/2

Answer 2

Answer:

Step-by-step explanation: