Answer:
77 nuts
Step-by-step explanation:
From the above question:
We have ratio
Peanuts : Almonds
The original mixture is given as:
A company offers a nut mixture with 4 peanuts for every 3 almonds.
4 : 3
The sum of the proportion = 7
Hence, there are 7 nuts in the container
The new mixture
The company changes the mixture to have 8 peanuts for every 3 almonds,
8 : 3
Sum of the proportion = 11
We are told : the number of nuts per container does not change.
How many nuts are in the smallest possible container?
To solve this, we use the Lowest Common Multiple principle
We find the L. C. M of 7 and 11
Multiples of 7:
7, 14, 21, 28, 35, 42, 49, 56, 63, 70, 77, 84, 91
Multiples of 11:
11, 22, 33, 44, 55, 66, 77, 88, 99
Therefore,
LCM(7, 11) = 77
Therefore, the number of nuts in the smallest possible container is 77 nuts
