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sveta [45]
3 years ago
9

The circumference of earth’s moon is about 1091500000 cm. Write this number in scientific notation

Mathematics
1 answer:
spayn [35]3 years ago
5 0

Answer:

The answer is 1.0915×10^9 cm

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I NEED ASAP DUE IN 20 MINS
11111nata11111 [884]

Answer:

y = 45 / 2x + 50

Step-by-step explanation:

The best equation for the line of the best fit would be y = 45 / 2x + 50.

The slope would be 45 / 2 and the y-intercept would be ( 0 , 50 ).

I used the points, ( 0 , 50 ) and ( 4 , 140 ) to get the equation, slope, and the y-intercept.

I used those points because they were the most accurate ones that I know for now.

Also, remember the formula is, "y = mx + b."

4 0
2 years ago
8x = 96<br> How would I solve for x
Vaselesa [24]

How to solve your problem

6 0
2 years ago
Read 2 more answers
what is the mistake in this problem and why is it wrong? 15+(√9•7)÷13 = 15+(3•7)÷3 = 15+(21)÷3 = 36+3 =12
Serggg [28]

[Edit:}

Okay! So after you have 15+(21)÷3, you have to remember PEMDAS.

PEMDAS is the order in which you solve equations.

1. Parentheses: you solve everything in the parentheses first, all while following the rules of PEMDAS

2. Exponents: after you solve the things in the parentheses, you do the exponents.

3. Then you do Multiplication or Division, solving in the order from left to right.

4. After, you do Addition or Subtraction, solving in the order from left to right.

So using PEMDAS, we'll solve 15+(21)÷3.

We do division before addition, so 21/3 is 7.

Then you add 15 to 7 and get 22 as your final answer.

Hope this helps!

7 0
3 years ago
(9-2x)+(6x+4) find the sum
aliya0001 [1]

Answer:

4x+13

Step-by-step explanation:

combine like terms -2x and 6x to get 4 then combine 9 and 4 to get 13

8 0
3 years ago
What is the coefficient of the x^5y^5- term in the biomial expansion of (2x-3y)^10
jasenka [17]

<u>Answer:</u>

 The coefficient of x^{5} \times y^{5} \text { is }=\left(252 \times 2^{5} \times(-3)^{5}\right)=252 \times 32 \times 243=1959552

<u>Solution: </u>

The given expression is (2 x-3 y)^{10}

As per binomial theorem, we know,

(x+y)^{n}=\sum n C_{k} x^{n-k} y^{k}

Now here a = 2x, b = (- 3y) and n = 10 and k = 0,1,2,….10

Now x^{5}\times y^5 will be the 6 term where k =5

Now, \mathrm{T}_{6}=10 \mathrm{C}_{5} \times(2 \mathrm{x})^{(10-5)} \times(-3 \mathrm{y})^{5}=10 \mathrm{C}_{5} 2^{5} \times \mathrm{x}^{5} \times(-3)^{5} \times \mathrm{y}^{5}

So, the coefficient of x^{5} \times y^{5} \text { is }=10\left(5 \times 2^{5} \times(-3)^{5}\right.

10 \mathrm{C}_{5}=\frac{10 !}{5 ! \times(10-5) !}=\frac{10 !}{5 !+5 !}=\frac{10 \times 9 \times 8 \times 7 \times 6 \times 5 !}{5 ! \times 5 !}=\frac{10 \times 9 \times 8 \times 7 \times 6}{5 \times 4 \times 3 \times 2 \times 1}=\left(\frac{30240}{120}\right)=252

The coefficient of x^{5} \times y^{5} \text { is }=\left(252 \times 2^{5} \times(-3)^{5}\right)=252 \times 32 \times 243=1959552

6 0
3 years ago
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