I think the answer would be c
Hello :
<span> sin 2x = sin x and 0 ≤ x ≤ 2π.
all solutions :
2x= x +2k</span>π or x= π -x +2kπ ..... k in : Z
x = 2kπ or : x = π/2 + kπ
but :
<span>0 ≤ x ≤ 2π
</span><span>all values of x such that sin 2x = sin x and 0 ≤ x ≤ 2π are :
</span>k = 0 : x=0 , x= π/2
k=1 : x=2 π , x=3π/2
Answer: I don't know if you wanted me to solve for C or F. But, I Solved for both.
Step-by-step explanation:
<u>Solved for F </u>
<u>Solved for C</u>
Subtract two from your get 2
Answer:
y=-2x
Step-by-step explanation:
First you want to remember rise over run. Your rise is -2 and your run is 1. So -2/1 is your answer. And -2/1 is equal to -2.
