Answer:
g =6/5 g=-5/2
Step-by-step explanation:
(5g − 6)(2g + 5) = 0
Using the zero product property
(5g − 6) =0 (2g + 5) = 0
5g-6+6 =0+6 2g+5-5=0-5
5g =6 2g =-5
5g/5 = 6/5 2g/2 =-5/2
g =6/5 g=-5/2
Answer:
7560
Step-by-step explanation:
I used google calculator
Line 1 is parallel and slope -1.33333 or -4/3
Line 2 is parallel and slope 0.75 or 6/8
Line 3 is parallel and slope 0.75 or -3/-4 i got the answers on Omni calculator
Answer:
The area of the roof: ≈2287.44 ft^2, the lateral area of the roof:≈1580.58 ft^2
Step-by-step explanation:
The area of the roof is computed by the equation of the area of a cone:
A = πr(r + 
)
(r: radius, h: height, πr^2 is the area of the base of the cone, πr is the lateral area of the cone). So:
A = 
≈ 2287.44 ft^2.
As I stated earlier, the lateral area of the roof can be computed:
A
=
≈ 1580.58 ft^2.
Answer:
A) The best way to picture this problem is with a probability tree, with two steps.
The first branch, the person can choose red or blue, being 2 out of five (2/5) the chances of picking a red marble and 3 out of 5 of picking a blue one.
The probabilities of the second pick depends on the first pick, because it only can choose of what it is left in the urn.
If the first pick was red marble, the probabilities of picking a red marble are 1 out of 4 (what is left of red marble out of the total marble left int the urn) and 3 out of 4 for the blue marble.
If the first pick was the blue marble, there is 2/4 of chances of picking red and 2/4 of picking blue.
B) So a person can have a red marble and a blue marble in two ways:
1) Picking the red first and the blue last
2) Picking the blue first and the red last
C) P(R&B) = 3/5 = 60%
Step-by-step explanation:
C) P(R&B) = P(RB) + P(BR) = (2/5)*(3/4) + (3/5)*(2/4) = 3/10 + 3/10 = 3/5
