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Maurinko [17]
3 years ago
5

Please help me in this!

Mathematics
1 answer:
Rudik [331]3 years ago
5 0

Answer:

5000

ghsjdjdjdjdjdjdjdkdkdkdkdkdkdkdk

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Find the equation, (f(x) = a(x - h)2 + k), for a parabola containing point (2, -1) and having (4, -3) as a vertex. What is the s
postnew [5]

Given that the vertex of the parabola is (4,-3)

The parabola passes through the point (2,-1)

We need to determine the standard form of the equation of the parabola.

<u>Standard form of the equation of the parabola:</u>

The standard form of the equation is y=a(x-h)^2+k where the vertex is (h,k) and a is the constant.

Substituting the vertex (4,-3) in the above equation, we get;

y=a(x-4)^2-3  ---------------(1)

Substituting the point (2,-1) in the above equation, we have;

-1=a(2-4)^2-3

-1=a(-2)^2-3

-1=4a-3

  2=4a

  \frac{1}{2}=a

Thus, the value of a is \frac{1}{2}

Substituting the value of a in the equation (1), we get;

y=\frac{1}{2}(x-4)^2-3

Thus, the standard form of the equation of the parabola is y=\frac{1}{2}(x-4)^2-3

3 0
3 years ago
Triangle XYZ has been enlarged and P as the center of dilation and scale to form a triangle X’ Y’ Z’
Maksim231197 [3]

Distances from the center of dilation are multiplied by the dilation factor. The appropriate choice is ...

... A. X'P/XP = Y'P/YP = Z'P/ZP

_____

We don't know what selection B means in this context.

Selection C will only be true if the dilation is by a factor of 2.

Selection D will only be true if P is the center of the circumscribing circle for both X'Y'Z' and XYZ.

6 0
4 years ago
The length of the hypotenuse in a 30°-60°-90° triangle is 6√10yd. What is the
ch4aika [34]

Answer:

Long leg = 3√30 yards.

Step-by-step explanation:

Ratio of the long leg to the hypotenuse = √3 to 2.

So (6√10) / x = 2 / √3

2x =  6√10√3

x = 3√10√3

x = 3√30

6 0
3 years ago
The table shows the running speeds of 10 randomly selected grizzly bears.
True [87]
The answer is Most likely D
8 0
3 years ago
Find S5 for the sequence 3, 13, 23, 33, 43, 53, 63, 73.
hoa [83]
 have an arithmetic sequence here....to find the common difference, subtract the first term from the second term. 13 - 3 = 10...so basically, ur adding 10 to each number to get to the next number.

before we find s5, we r going to find a5...because we need a5 to use in the sum formula.....a5 is the fifth term, and it is 43

sn = (n (a1 + a5) / 2
s5 = (5 (3 + 43) / 2
s5 = (5 (46)) / 2
s5 = 230/2
s5 = 115 <===

or, for this particular problem, s5 is the sum of the first 5 terms.
3 + 13 + 23 + 33 + 43 = 115.....u can do it this way for s5...but if u were asked to find s20, I suggest using the formula.
3 0
4 years ago
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