Relations are subsets of products <span><span>A×B</span><span>A×B</span></span> where <span>AA</span> is the domain and <span>BB</span> the codomain of the relation.
A function <span>ff</span> is a relation with a special property: for each <span><span>a∈A</span><span>a∈A</span></span> there is a unique <span><span>b∈B</span><span>b∈B</span></span> s.t. <span><span>⟨a,b⟩∈f</span><span>⟨a,b⟩∈f</span></span>.
This unique <span>bb</span> is denoted as <span><span>f(a)</span><span>f(a)</span></span> and the 'range' of function <span>ff</span> is the set <span><span>{f(a)∣a∈A}⊆B</span><span>{f(a)∣a∈A}⊆B</span></span>.
You could also use the notation <span><span>{b∈B∣∃a∈A<span>[<span>⟨a,b⟩∈f</span>]</span>}</span><span>{b∈B∣∃a∈A<span>[<span>⟨a,b⟩∈f</span>]</span>}</span></span>
Applying that on a relation <span>RR</span> it becomes <span><span>{b∈B∣∃a∈A<span>[<span>⟨a,b⟩∈R</span>]</span>}</span><span>{b∈B∣∃a∈A<span>[<span>⟨a,b⟩∈R</span>]</span>}</span></span>
That set can be labeled as the range of relation <span>RR</span>.
Here is the information for the stem-and-leaf plot you gave:
Median: 5
Range: 10
Mean: 6.08
Mode: 8
I don't see where the answers you provided would fit with this at all.
Answer:
There are 52 such numbers that have even divisors.
Step-by-step explanation:
All the numbers between 2 and 59 have an EVEN number of positive divisors.
Except the Perfect Squares..
or 4, 9, 16, 25, 36 and 49, which have 3 divisors each.
So:
59 - 2 + 1 =58
Now subtract 58 from 6 (perfect squares)
58- 6=52
Therefore,it means that there are 52 such numbers that have EVEN divisors....
Answer:
800 × 7 + 60 × 7 + 2 × 7
Step-by-step explanation:
The area of the figure equals :
Area of rectangle = Length * width
Width = 7
Length = 862
862 in expanded form:
800 + 60 + 2
Hence, Multiplying the expanded form by the width ;
(800 + 60 + 2) * 7
800*7 + 60*7 + 2*7
