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Deffense [45]
3 years ago
13

Quick help plzz!!!!!!!

Mathematics
1 answer:
kvv77 [185]3 years ago
3 0
It is B I’m pretty sure
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Two trains leave towns 912 kilometers apart at the same time and travel toward each other. One train travels 12
Lady bird [3.3K]

Answer:

Step-by-step explanation:

Remark

The two trains are travelling towards each other. That means that their total distance = 912 km. Neither one has gone that distance by itself. The effect this has on the question is that you add the two rates multiplied by time.

Givens

r1 = x

r2 = x + 12

t = 3 hours

d = 912 km

Equation

d = r * t

r1 * t + r2 * t = 912

Solution

3x    + 3*(x + 12) = 912          Remove the brackets

3x +  3x + 36 = 912              Combine like terms

6x + 36 =   912                     Subtract 36 from both sides

 <u>     -36      -36</u>

6x       =      876                   Divide both sides by 6  

6x/6   =       876/6

x =               146 km/h

Answer

Slow train = 146 km/hr

Fast train = 146 + 12 = 158 km/hr

5 0
3 years ago
Un industrial obtiene un préstamo de $ 15.000, al 23% anual por el lapso de 5 años. Calcular el monto a la finalización de este
olasank [31]

Answer:

$18,781.5

Step-by-step explanation:

According to the problem, calculation of the given data are as follows,

Loan amount (P) = $15,000

Rate of interest (r) = 23%

Time (t) = 5 years

Let this loan is compounding annually, then the amount after 5 years can be calculated as follows,

Final amount = P  (1 + ( r/t))^{t}

by putting the value in formula, we get

= $15,000 (  (1 + ( 0.23/5))^{5}

= $15,000 × 1.2521

= $18,781.5

4 0
3 years ago
Name the vertex for this parabola. *<br> y = (x + 6)^2 + 15
Aleks04 [339]
The vertex would be (-6,15)
8 0
3 years ago
What is the answer to this?
zepelin [54]

To find the y-intercept substitute x as 0

y = 1 \times  {0}^{2}  + 7 \times 0 - 5

y = 1 \times 0 + 0 - 5

y = 0 + 0 - 5

y =  - 5

  • <em>Thus, The y-intercept is -5...~</em>
4 0
3 years ago
Read 2 more answers
Help. I need help with these questions ( see image).<br> Please show workings.
Andrew [12]

9514 1404 393

Answer:

  4)  6x

  5)  2x +3

Step-by-step explanation:

We can work both these problems at once by finding an applicable rule.

  \text{For $f(x)=ax^n$}\\\\\lim\limits_{h\to 0}\dfrac{f(x+h)-f(x)}{h}=\lim\limits_{h\to 0}\dfrac{a(x+h)^n-ax^n}{h}\\\\=\lim\limits_{h\to 0}\dfrac{ax^n+anx^{n-1}h+O(h^2)-ax^n}{h}=\boxed{anx^{n-1}}

where O(h²) is the series of terms involving h² and higher powers. When divided by h, each term has h as a multiplier, so the series sums to zero when h approaches zero. Of course, if n < 2, there are no O(h²) terms in the expansion, so that can be ignored.

This can be referred to as the <em>power rule</em>.

Note that for the quadratic f(x) = ax^2 +bx +c, the limit of the sum is the sum of the limits, so this applies to the terms individually:

  lim[h→0](f(x+h)-f(x))/h = 2ax +b

__

4. The gradient of 3x^2 is 3(2)x^(2-1) = 6x.

5. The gradient of x^2 +3x +1 is 2x +3.

__

If you need to "show work" for these problems individually, use the appropriate values for 'a' and 'n' in the above derivation of the power rule.

3 0
3 years ago
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