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CaHeK987 [17]
3 years ago
9

I need some help with this problem.

Mathematics
1 answer:
AnnZ [28]3 years ago
5 0
So we are dealing with a 30-60-90 triangle obviously. This is one of those triangles that always has the same ratio of their sides which means if you know one side length of a 30-60-90 you know all the sides.


I have attached a diagram of a 30-60-90 triangle below, we can use it to find the different sides
.

1. 2x =AB and x = BC, we know AB=14, since AB is two times as big as BC we know that BC = 7


2. Knowing BC equals 7 we can also say that x=7, since the diagram shows us AC = x times the square root of three we know that AC = 7 times the square root of 3.


3. If AB =16, 16 = 2x, and x=8, plug this into x times the square root of three to get AC, which equals 8 times the square root of three.


4. If AC equals 9 times the square root of three, we know that x=9. Side BC is simply x so BC = 9

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Answer:

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6 0
3 years ago
Find the diameter of a circle with the known circumference of 314” use the formula d= C
siniylev [52]

The complete formula for circumference is:


C=\pi d


Since we know the circumference of the circle is 314 inches, we can then solve for d, the diameter:


314=\pi d


Using 3.14 for pi, we get:


314=(3.14)d


Then solve for d:


d=100


And now we know the diameter of the circle is 100 inches.

4 0
3 years ago
Only need to answer question 1 but if you can pls answer both
algol [13]
Use the app photo map
5 0
3 years ago
What is the value of the digit 3 in the # 2314^5
Nana76 [90]
Are you asking like thousands or something else?

3 0
3 years ago
(08.07 HC)
andreev551 [17]

Answer:

\textsf{A)} \quad x=-2, \:\:x=\dfrac{5}{2}

\textsf{B)} \quad \left(\dfrac{1}{4},-\dfrac{81}{8}\right)=(0.25,-10.125)

C)  See attachment.

Step-by-step explanation:

Given function:

f(x)=2x^2-x-10

<h3><u>Part A</u></h3>

To factor a <u>quadratic</u> in the form  ax^2+bx+c<em> , </em>find two numbers that multiply to ac and sum to b :

\implies ac=2 \cdot -10=-20

\implies b=-1

Therefore, the two numbers are -5 and 4.

Rewrite b as the sum of these two numbers:

\implies f(x)=2x^2-5x+4x-10

Factor the first two terms and the last two terms separately:

\implies f(x)=x(2x-5)+2(2x-5)

Factor out the common term  (2x - 5):

\implies f(x)=(x+2)(2x-5)

The x-intercepts are when the curve crosses the x-axis, so when y = 0:

\implies (x+2)(2x-5)=0

Therefore:

\implies (x+2)=0 \implies x=-2

\implies (2x-5)=0 \implies x=\dfrac{5}{2}

So the x-intercepts are:

x=-2, \:\:x=\dfrac{5}{2}

<h3><u>Part B</u></h3>

The x-value of the vertex is:

\implies x=\dfrac{-b}{2a}

Therefore, the x-value of the vertex of the given function is:

\implies x=\dfrac{-(-1)}{2(2)}=\dfrac{1}{4}

To find the y-value of the vertex, substitute the found value of x into the function:

\implies f\left(\dfrac{1}{4}\right)=2\left(\dfrac{1}{4}\right)^2-\left(\dfrac{1}{4}\right)-10=-\dfrac{81}{8}

Therefore, the vertex of the function is:

\left(\dfrac{1}{4},-\dfrac{81}{8}\right)=(0.25,-10.125)

<h3><u>Part C</u></h3>

Plot the x-intercepts found in Part A.

Plot the vertex found in Part B.

As the <u>leading coefficient</u> of the function is positive, the parabola will open upwards.  This is confirmed as the vertex is a minimum point.

The axis of symmetry is the <u>x-value</u> of the <u>vertex</u>.  Draw a line at x = ¹/₄ and use this to ensure the drawing of the parabola is <u>symmetrical</u>.

Draw a upwards opening parabola that has a minimum point at the vertex and that passes through the x-intercepts (see attachment).

5 0
2 years ago
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