Answer:
m= -1
I hope this helped, have a great day!! <3
Answer: Hello!
Let's start with the word TRISKAIDEKAPHOBIA wich has 17 letters (some of them repeat, but it does not matter in this problem)
We want to know how many permutations we can do with 17 letters: then think this way, Lets compose a word. The first letter of this word has 17 options, the second letter of the word has 16 options (you already took one of the set) the third letter of the word has 15 options, and so on.
The total number of permutations is the product of the number of options that you have for each letter, this is:
17*16*15*14*....*3*2*1 = 17! = 3.6e+14
(b) FLOCCINAUCINIHILIPILIFICATION now we have 30 letters in total, using the same reasoning as before, here we have 30! permutations; this is
30! = 2.65e+32
(c) PNEUMONOULTRAMICROSCOPICSILICOVOLCANOCONIOSIS: now there are 47 letters.
then P = 47! = 2.59e+59
(d) DERMATOGLYPHICS: here are 18 letters, then:
p = 18! = 6.4e+15
Answer:
I'm not very sure, however I think you have to replace the sign - for a +.
Step-by-step explanation:
7 + 4√13
Answer: c)
Step-by-step explanation:
This can be done through trial-and-error. Use the pythagoreas' theorem and if the left side of the equation is equal to the right, that is the answer.
(Do take note that c is the longest side.)
a)
Since , a) is wrong.
b)
Since , b) is wrong.
c) (answer)
Since , c) is correct.
d)
Since , d) is wrong.
Answer:
65.9734457254 or 65.97
Step-by-step explanation:
c= pi x diameter
c= pi x (10.5 x 2)
c= pi x 21
= 65.9734457254