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Anna007 [38]
3 years ago
11

Are the data shown in this line plot skewed left, skewed right, or not skewed?

Mathematics
2 answers:
bekas [8.4K]3 years ago
8 0
<u />The data is <u>Skewed right</u><u /> since most of the data is on the left side, the right side points are screwing up the mean and median.
ivanzaharov [21]3 years ago
4 0

Answer with explanation:

Writing the data values which is represented on the line plot

0,0,0,0,1,1,1,1,1,2,2,2,2,2,2,2,2,3,3,3,3,4,4,5,8,10

There are 26 variate in the data set.

Mean of the data set is

M=\frac{0\times 4 +1\times 5 +2\times 8+3\times 4+4\times 2+5\times 1+8\times 1+10\times 1}{26}\\\\=\frac{0+5+16+12+8+5+8+10}{26}\\\\=\frac{64}{26}\\\\=2.47

Median ,as there are even number of variate in the data set

   =\frac{2+2}{2}\\\\=2

Mode , which is maximum number of times occurring variate in the data set

=2

→Mean > Median and Mode

So, Data is Skewed Right.

     

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Two word phrases for each expression t+32
mixas84 [53]
A number plus 32.
The sum of a number and 32.
8 0
3 years ago
Given: KLMN is a trapezoid m∠N = m∠KML ME ⊥ KN , ME = 3 5 , KE = 8, LM KN = 3 5 Find: KM, LM, KN, Area of KLMN
prisoha [69]
A) Find KM∠KEM is a right angle hence ΔKEM is a right angled triangle Using Pythogoras' theorem where the square of hypotenuse is equal to the sum of the squares of the adjacent sides we can answer the 
KM² = KE² + ME²KM² = 8² + (3√5)²       = 64 + 9x5KM = √109KM = 10.44
b)Find LMThe ratio of LM:KN is 3:5 hence if we take the length of one unit as xlength of LM is 3xand the length of KN is 5x ∠K and ∠N are equal making it a isosceles trapezoid. A line from L that cuts KN perpendicularly at D makes KE = DN
KN = LM + 2x 2x = KE + DN2x = 8+8x = 8LM = 3x = 3*8 = 24
c)Find KN Since ∠K and ∠N are equal, when we take the 2 triangles KEM and LDN, they both have the same height ME = LD.
∠K = ∠N  Hence KE = DN the distance ED = LMhence KN = KE + ED + DN since ED = LM = 24and KE + DN = 16KN = 16 + 24 = 40
d)Find area KLMNArea of trapezium can be calculated using the  formula below Area = 1/2 x perpendicular height between parallel lines x (sum of the parallel sides)substituting values into the general equationArea = 1/2 * ME * (KN+ LM)          = 1/2 * 3√5 * (40 + 24)         = 1/2 * 3√5 * 64         = 3 x 2.23 * 32         = 214.66 units²
7 0
3 years ago
During a seven day winter storm, snow fall levels were recorded in this table. What was the average snowfall for those days?
Pavel [41]

Answer:

45.98

Step-by-step explanation:

7 0
3 years ago
Can someone help me in this plssss I really need it
kompoz [17]

Answer:

\boxed{-3xy^{2}\sqrt [3] {2x^{2}}}

Step-by-step explanation:

Your expression is

\sqrt [3] {-54x^{5}y^{6}}

Here's how I would simplify it.

\begin{array}{rcll}\sqrt [3] {-54x^{5}y^{6}} & = & \sqrt [3] {(-1)^{3}\times 2 \times 27 \times x^{2} \times x^{3} \times y^{6}} & \text{Factored the cubes}\\& = & \sqrt [3] {(-1)^{3} \times 3^{3}\times x^{3} \times y^{6}\times 2 \times x^{2}} & \text{Grouped the cubes}\\\end{array}

\begin{array}{rcll}& = & \sqrt [3] {(-1)^{3} \times {3^{3}\times x^{3} \times y^{6}}} \times\sqrt [3] { 2 \times x^{2}} & \text{Separated the cubes}\\&=& \mathbf{-3xy^{2}\sqrt [3] {2x^{2}}} & \text{Took cube roots}\\\end{array}

\text{The simplified expression is $\boxed{\mathbf{-3xy^{2}\sqrt [3] {2x^{2}}}}$}

6 0
4 years ago
Sorry for the last one but i need help on this asap please
PilotLPTM [1.2K]

Answer:

133.3 (1. dp)

Step-by-step explanation:

First of all we subtract 36 from 60 which is 24 then you divide 24 by 0.18 as its the remaining money divided by the value per mile which gives you the answer: 133.333333 which is rounded

Would be amazing if you marked brainliest :)

6 0
3 years ago
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