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Wittaler [7]
3 years ago
7

Which is bigger -1 1/2 or -1/2

Mathematics
1 answer:
bixtya [17]3 years ago
5 0

Answer:

-1/2

Step-by-step explanation:

just trust me, idk how to explain it

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The point (-4,4) is a solution for the system contains lines ____and ____
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Step-by-step explanation:

B and C

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Please answer this these are all the points i got left XD
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Answer is choice B

The ratio of the sides (first to the second) is 11/9 since we divide 22/18 and reduce that fraction

Once we know the scale factor is 11/9, we square it to get (11/9)^2 = 121/81 which is the ratio of the first area to the second area
3 0
3 years ago
The shape has no right angles all the sides are congruent the total of its angle is less than 360°
amm1812

Answer:

equilateral triangle

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3 years ago
What is the Median for the following set of numbers? ​21 23 76 47 55 135 45 30 17
Leno4ka [110]

Answer:

Median = 45

Step-by-step explanation:

We are given the following data set:

21, 23, 76, 47, 55, 135, 45, 30, 17

Median is the number that divides the data into two equal parts.

Formula:

Median:\\\text{If n is odd, then}\\\\Median = \displaystyle\frac{n+1}{2}th ~term \\\\\text{If n is even, then}\\\\Median = \displaystyle\frac{\frac{n}{2}th~term + (\frac{n}{2}+1)th~term}{2}

Sorted data:

17, 21, 23, 30, 45, 47, 55, 76, 135

Sample size = 9, which is odd

Median =

\dfrac{9+1}{2}^{th}\text{ term} = \dfrac{10}{2}^{th}\text{ term} = 5^{th}\text{ term}\\\\= 45

The median of given set of numbers is 45.

7 0
3 years ago
Solve step by step solution then only i can do it plxx ​
Anuta_ua [19.1K]

Answer:

<h3><u>Let's</u><u> </u><u>understand the concept</u><u>:</u><u>-</u></h3>

Here angle B is 90°

So \triangle ABC and \triangle ABD Are right angled triangle

So we use Pythagoras thereon for solution

<h3><u>Required Answer</u><u>:</u><u>-</u></h3>
  • First in triangle ABC

perpendicular=p=8cm

Hypontenuse =h =10cm

  • We need to find base=b

According to Pythagoras thereon

{\boxed{\sf b^2=h^2-p^2}}

  • Substitutethe values

\longrightarrow\sf b^2=10^2-p^2

\longrightarrow\sf b={\sqrt {10^2-8^2}}

\longrightarrow\sf b={\sqrt{100-64}}

\longrightarrow\bf b={\sqrt {36}}

\longrightarrow\sf b=6

\therefore\overline{BC}=6cm

  • BD=BC+CD

\longrightarrowBD=9+6

\longrightarrowBD=15cm

  • Now in \triangle ABD

Perpendicular=p=8cm

Base =b=15cm

  • We need to find Hypontenuse =AD(x)

According to Pythagoras thereon

{\boxed {\sf h^2=p^2+b^2}}

  • Substitute the values

\longrightarrow\sf h^2=8^2+15^2

\longrightarrow\sf h={\sqrt {8^2+15^2}}

\longrightarrow\sf h={\sqrt {64+225}}

\longrightarrow\sf h={\sqrt {289}}

\longrightarrow\sf h=17cm

\therefore{\underline{\boxed{\bf x=17cm}}}

3 0
3 years ago
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