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3 years ago

Fill in the missing numbers to complete the division problem.Enter your answers in the boxes.6,957\div 7=6,957÷7=Remainder:

Mathematics

1 answer:

dimaraw [331]3 years ago

4 0

Answer:

Step-by-step explanation:

why because when you work this out 6,957÷7 your answer will be 993.8571...

so you take the hole number of the decimal and multiply it by 7 the answer should be subtracted from 6,957

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What is tan 11 pie/6

tia_tia [17]

Answer:

5.75

Step-by-step explanation:

5 0

3 years ago

Find the mass and center of mass of the lamina that occupies the region D and has the given density function rho. D is the trian

Alla [95]

Answer: mass (m) = 4 kg

center of mass coordinate: (15.75,4.5)

Step-by-step explanation: As a surface, a lamina has 2 dimensions (x,y) and a density function.

The region D is shown in the attachment.

From the image of the triangle, lamina is limited at x-axis: 0≤x≤2

At y-axis, it is limited by the lines formed between (0,0) and (2,1) and (2,1) and (0.3):

Points (0,0) and (2,1):

y = $\frac{1-0}{2-0}(x-0)$

y = $\frac{x}{2}$

Points (2,1) and (0,3):

y = $\frac{3-1}{0-2}(x-0) + 3$

y = -x + 3

Now, find total mass, which is given by the formula:

$m = \int\limits^a_b {\int\limits^a_b {\rho(x,y)} \, dA }$

Calculating for the limits above:

$m = \int\limits^2_0 {\int\limits^a_\frac{x}{2} {2(x+y)} \, dy \, dx }$

where a = -x+3

$m = 2.\int\limits^2_0 {\int\limits^a_\frac{x}{2} {(xy+\frac{y^{2}}{2} )} \, dx }$

$m = 2.\int\limits^2_0 {(-x^{2}-\frac{x^{2}}{2}+3x )} \, dx }$

$m = 2.\int\limits^2_0 {(\frac{-3x^{2}}{2}+3x)} \, dx }$

$m = 2.(\frac{-3.2^{2}}{2}+3.2-0)$

m = 2(-4+6)

m = 4

Mass of the lamina that occupies region D is 4.

Center of mass is the point of gravity of an object if it is in an uniform gravitational field. For the lamina, or any other 2 dimensional object, center of mass is calculated by:

$M_{x} = \int\limits^a_b {\int\limits^a_b {y.\rho(x,y)} \, dA }$

$M_{y} = \int\limits^a_b {\int\limits^a_b {x.\rho(x,y)} \, dA }$

$M_{x}$ and $M_{y}$ are moments of the lamina about x-axis and y-axis, respectively.

Calculating moments:

For moment about x-axis:

$M_{x} = \int\limits^a_b {\int\limits^a_b {y.\rho(x,y)} \, dA }$

$M_{x} = \int\limits^2_0 {\int\limits^a_\frac{x}{2} {2.y.(x+y)} \, dy\, dx }$

$M_{x} = 2\int\limits^2_0 {\int\limits^a_\frac{x}{2} {y.x+y^{2}} \, dy\, dx }$

$M_{x} = 2\int\limits^2_0 { ({\frac{y^{2}x}{2}+\frac{y^{3}}{3})}\, dx }$

$M_{x} = 2\int\limits^2_0 { ({\frac{x(-x+3)^{2}}{2}+\frac{(-x+3)^{3}}{3} -\frac{x^{3}}{8}-\frac{x^{3}}{24} )}\, dx }$

$M_{x} = 2.(\frac{-9.x^{2}}{4}+9x)$

$M_{x} = 2.(\frac{-9.2^{2}}{4}+9.2)$

$M_{x} = 18$

Now to find the x-coordinate:

x = $\frac{M_{y}}{m}$

x = $\frac{63}{4}$

x = 15.75

For moment about the y-axis:

$M_{y} = \int\limits^2_0 {\int\limits^a_\frac{x}{2} {2x.(x+y))} \, dy\,dx }$

$M_{y} = 2.\int\limits^2_0 {\int\limits^a_\frac{x}{2} {x^{2}+yx} \, dy\,dx }$

$M_{y} = 2.\int\limits^2_0 {y.x^{2}+x.{\frac{y^{2}}{2} } } \,dx }$

$M_{y} = 2.\int\limits^2_0 {x^{2}.(-x+3)+\frac{x.(-x+3)^{2}}{2} - {\frac{x^{3}}{2}-\frac{x^{3}}{8} } } \,dx }$

$M_{y} = 2.\int\limits^2_0 {\frac{-9x^3}{8}+\frac{9x}{2} } \,dx }$

$M_{y} = 2.({\frac{-9x^4}{32}+9x^{2})$

$M_{y} = 2.({\frac{-9.2^4}{32}+9.2^{2}-0)$

$M{y} =$ 63

To find y-coordinate:

y = $\frac{M_{x}}{m}$

y = $\frac{18}{4}$

y = 4.5

Center mass coordinates for the lamina are (15.75,4.5)

3 0

4 years ago

Dan Perkins goat is attached to the corner of the 8-foot-by-4-foot pump house by QN 8-foot length of rope. The goat eats the gra

SashulF [63]

The goat is tied in the four corners of an 8-foot by 4-foot pump house. The rope is 8 feet. The goat is eating the grass, forming a circle The pattern is 3/4 of a circle radius 8 and 1/4 of a circle radius 4.

Getting the area of radius of 8 feet
Area = pi * r^2
Area = pi * 8^2
Area = 201.06 feet^2

Getting the area of radius of 4 feet
Area = pi * r^2
Area = pi * 4^2
Area = 50.27 feet^2

3/4 of 201.06 = 150.80 feet ^2
1/4 of 50.27 = 12.60 feet^2

So the total area is 153.40 feet^2

8 0

3 years ago

What is the volume of the sphere shown below with a radius of 3?

garri49 [273]

Answer: 113.1

Step-by-step explanation: v=4/3(pie)r^3=4/3•(pie)•3^3= 113.09734

3 0

3 years ago

In a certain month a family spent $750 on food .In third month the family spent $729 on food .What was percentage decrease in th

seraphim [82]

Answer: 2.8%

Step-by-step explanation:

Give, In a certain month a family spent $750 on food

In third month the family spent $729 on food .

i.e. Expenditure on food in a certain month = $750

Expenditure on food in third month = $729

Decrease in monthly spending on food = (Expenditure in a certain month )- (Expenditure in third month )

= $750 - $729

= $21

Now , the percentage decrease in the month spent on food will be :

$\dfrac{\text{Decrease in monthly spending on food }}{\text{Expenditure on food in a certain month}}\times100\\\\=\dfrac{21}{750}\times100\\\\=2.8\%$

Hence, the percentage decrease in the month spent on food is 2.8%.

3 0

4 years ago

Fill in the missing numbers to complete the division problem.​Enter your answers in the boxes.6,957\div 7=6,957÷7=Remainder:

Fill in the missing numbers to complete the division problem.Enter your answers in the boxes.6,957\div 7=6,957÷7=Remainder: