Question

Find the perimeter of a right triangle whose legs are 6cm and 8cm

Answer 1

P = Perimeter

A = 1 leg

B = 2 leg

$P = a + b + \sqrt{ {a}^{2} + {b}^{2} } \\ = 6 + 8 + \sqrt{ {6}^{2} + {8}^{2} } \\ = 14 + \sqrt{ {6}^{2} + {8}^{2} } \\ = 24cm$

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