<h2> 2.10</h2><h2>+0.59</h2>
₋₋₋₋₋₋₋₋₋₋₋₋
<h2><em>2.69</em></h2>
Answer:
a) x = 1225.68
b) x = 1081.76
c) 1109.28 < x < 1198.72
Step-by-step explanation:
Given:
- Th random variable X for steer weight follows a normal distribution:
X~ N( 1154 , 86 )
Find:
a) the highest 10% of the weights?
b) the lowest 20% of the weights?
c) the middle 40% of the weights?
Solution:
a)
We will compute the corresponding Z-value for highest cut off 10%:
Z @ 0.10 = 1.28
Z = (x-u) / sd
Where,
u: Mean of the distribution.
s.d: Standard deviation of the distribution.
1.28 = (x - 1154) / 86
x = 1.28*86 + 1154
x = 1225.68
b)
We will compute the corresponding Z-value for lowest cut off 20%:
-Z @ 0.20 = -0.84
Z = (x-u) / sd
-0.84 = (x - 1154) / 86
x = -0.84*86 + 1154
x = 1081.76
c)
We will compute the corresponding Z-value for middle cut off 40%:
Z @ 0.3 = -0.52
Z @ 0.7 = 0.52
[email protected] < x < [email protected]
-.52*86 + 1154 < x < 0.52*86 + 1154
1109.28 < x < 1198.72
The answer is in the picture
Sorry I can’t copy and pasted it here
Answer: Last option.
Step-by-step explanation:
Given the equation:
Follow these steps to solve it:
- Subtract the fractions on the left side of the equation:
- Using the Difference of squares formula (
) we can simplify the denominator of the right side of the equation:
- Multiply both sides of the equation by 
and simplify:
- Multiply both sides by 
:
- Apply Distributive property and simplify:
- Divide both sides of the equation by -6:
- Factor the equation and solve for "m":
In order to verify it, you must substitute 
into the equation and solve it:
<em>NO SOLUTION</em>
3x : 2 = 15
3x = 15 * 2
3x = 30
x = 30 : 3
x = 10
--------------------------------
3(10) :2 = 15
