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nalin [4]
2 years ago
8

If Luke's brother earns $15 per hour, he will get a 6% increase per hour. How

Mathematics
1 answer:
jeka942 years ago
5 0
Luke’s brother will now make $15.90 per hour.
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HELP ASAP! The number of entertainment websites in 1995 wass 54. By 2004 there were 793 entertainment website..
AleksandrR [38]
<h3>Answer: Choice A. 82 websites per year</h3>

=============================================================

How I got that answer:

We have gone from 54 websites to 793 websites. This is a change of 793-54 = 739 new websites. This is over a timespan of 2004-1995 = 9 years.

Since we have 739 new websites over the course of 9 years, this means the rate of change is 739/9 = 82.1111... where the '1's go on forever. Rounding to the nearest whole number gets us roughly 82 websites a year.

----------

You could use the slope formula to get the job done. This is because the slope represents the rise over run

slope = rise/run

The rise is how much the number of websites have gone up or down. The run is the amount of time that has passed by. So slope = rise/run = 739/9 = 82.111...

In a more written out way, the steps would be

slope = rise/run

slope = (y2-y1)/(x2-x1)

slope = (793 - 54)/(2004 - 1995)

slope = 739/9

slope = 82.111....

3 0
3 years ago
Make a conjecture about the next item in each sequence <br><br> -2, 1 , -1/2, 1/4, -1/8
Georgia [21]

Answer:

-2,2 -1/3 1/4 -1/9

4 0
3 years ago
Read 2 more answers
Don opened a checking account. Let F represent the
Law Incorporation [45]

Answer:

B and E

Step-by-step explanation:

In the function f(m)= -50m+300

-50 is the gradient meaning it is the rate of change per month. This means that the rate of change is -50 since this is the coefficient of m.

Also, -50m must be negative since m represents a month and you cant have negative months, so you know that the amount of money is decreasing

6 0
3 years ago
Combine like terms 9y−4
alexgriva [62]

Answer: i dont this you can combine like terms for this question because none of these have the same variable or anything.

5 0
2 years ago
Read 2 more answers
Help please!! How do I solve this
egoroff_w [7]
This is an exponential equation. We will solve in the following way. I do not have special symbols, functions and factors, so I work in this way
 2 on (2x) - 5 2 on x + 4=0 =>. (2 on x)2 - 5 2 on x + 4=0  We will replace expression ( 2 on x) with variable t => 2 on x=t  =. t2-5t+4=0 => This is quadratic equation and I solve this in the folowing way => t2-4t-t+4=0 =>     t(t-4) - (t-4)=0 => (t-4) (t-1)=0 => we conclude t-4=0 or t-1=0 => t'=4 and t"=1 now we will return t' => 2 on x' = 4 => 2 on x' = 2 on 2 => x'=2 we do the same with t" => 2 on x" = 1 => 2 on x' = 2 on 0 => x" = 0 ( we know that every number on 0 gives 1). Check 1: 2 on (2*2)-5*2 on 2 +4=0 =>                   2 on 4 - 5 * 4+4=0 => 16-20+4=0 =. 0=0 Identity proving solution. 
Check 2:   2 on (2*0) - 5* 2 on 0 + 4=0 => 2 on 0 - 5 * 1 + 4=0 => 
1-5+4=0 => 0=0  Identity provin solution.
5 0
3 years ago
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