Answer:
CLASS FREQUENCIES RELATIVE FREQUENCIES
A 60 0.5
B 12 0.1
C 48 0.4
TOTAL 120 1
Step-by-step explanation:
Given that;
the frequencies of there alternatives are;
Frequency A = 60
Frequency B = 12
Frequency C = 48
Total = 60 + 12 + 48 = 120
Now to determine our relative frequency, we divide each frequency by the total sum of the given frequencies;
Relative Frequency A = Frequency A / total = 60 / 120 = 0.5
Relative Frequency B = Frequency B / total = 12 / 120 = 0.1
Relative Frequency C = Frequency C / total = 48 / 120 = 0.4
therefore;
CLASS FREQUENCIES RELATIVE FREQUENCIES
A 60 0.5
B 12 0.1
C 48 0.4
TOTAL 120 1
Answer:
D. (6) is the distance between 6 and 0, and the distance is negative from 6 to 0
Step-by-step explanation:
(6) means the number exists in the negative state. It is -6.
Option A - As it is -6, it cannot be greater than positive 6. So, it is incorrect.
Option B - As it is -6, it cannot be less than negative 6. So, it is wrong.
Option C - As it is -6, its distance cannot be 0 to 6, and it should not be positive.
Option D - As it is -6, its distance should be negative and the distance is from 6 to 0. Therefore, it is the correct answer.
Numbers multiplied kwiwiijwi
Answer:
ME LOL
Step-by-step explanation:
XDHJCVEFBV,RW
Center: 0,0
vertex: 5,0
vertex2 (-5,0)
