Answer:
Correct option: (C) The 75th percentile is approximately 0.67
Step-by-step explanation:
The <em>p</em>th percentile is a data value such that at least <em>p</em>% of the data set is less than or equal to this data value and at least (100 - <em>p</em>)% of the data set are more than or equal to this data value.
If <em>x</em> is the <em>p</em>th percentile of a data set then,
P (X < x) = p/100
If 
then 
, is a standard normal variate with mean, E (Z) = 0 and Var (Z) = 1. That is, 
.
- The 90th percentile of a standard normal distribution is:
P (Z < z) = 0.90, then <em>z</em> = 1.28
- The 10th percentile of a standard normal distribution is:
P (Z < z) = 0.10, then <em>z</em> = -1.28
- The 75th percentile of a standard normal distribution is:
P (Z < z) = 0.75, then <em>z</em> = 0.67
- The 15th percentile of a standard normal distribution is:
P (Z < z) = 0.15, then <em>z</em> = -1.04
Thus, the correct statement is (C).
Answer:
Therefore 0.006 inches of rain will have fallen after 2 minutes.
Step-by-step explanation:
Given that,
y = 0.003x
where y is the number of inches of rain after x minutes.
To find the number of inches of rain after 2 minutes, we plug x = 2 minutes in above model equation.
∴ y= 0.003×2
=0.006
Therefore 0.006 inches of rain will have fallen after 2 minutes.
<span>a. Calculate the slope for this drain pipe.
1/22
b. A rainwater pipe 30 feet long must run under the edge of a roof. What is the minimum vertical distance the pipe must drop between its ends?
Turn 30 feet to inches so 30 * 12 = 360 inches
Now times 1/22 x 360 = 16.32 inches . If they want it in feet just change 16.32 to feet by dividing 16.32 / 12
c. A design calls for a drainage pipe to cross a building 45 feet wide as it drops 25 inches. Is this pip steep enough to function properly? Explain.
Change 45 feet to inches so 45 * 12 = 540
Now times 540 * 1/22 = 24.54 inches so 25 inches would be steep enough since it droops 25 inches. </span>
Answer:
I hope that is useful for you :)
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Answer:
1750 m²
Step-by-step explanation:
Dimension of tin box = 4m * 3.5 m * 3m
Length, l = 4 ; width, W = 3.5 ; height, h = 3
Total Surface area= 2(lw * lh * wh)
= 2((4*3.5) + (3.5*3) + (3.5 * 3))
= 70 m³
Area required to make 25 ;
25 * 70m³
= 1750 m³
