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2 years ago

(1000÷1)×10-5000 Giving brainliest

Mathematics

2 answers:

Marizza181 [45]2 years ago

8 0

Answer: The answer is 5000

Darya [45]2 years ago

3 0

Answer:

5000

Step-by-step explanation:

1000 divided by 1 = 1000

1000 x 10 = 10000

10000 - 5000 = 5000

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Convert 1/15 into a decimal correct to 2 decimal places

Citrus2011 [14]

Answer:

$\frac{1}{15} = 0.\overline{66}$

Step-by-step explanation:

We proceed to show the procedure to calculate the given fraction into a decimal form:

1) Since numerator is less than denominator, the integer component of the decimal number is zero:

$\frac{1}{15} = 0.xx$

2) We multiply the numerator by 10 and find the tenth digit:

$\frac{10}{15} = 0$

Then,

$\frac{1}{15} = 0.0xx$

3) We multiply the fraction in 2) by 10 and find the hundredth digit:

$\frac{100}{15} = 6$

Then,

$\frac{1}{15} = 0.66x$

And the remainder is:

$r = 100-15\times 6$

$r = 10$

4) We multiply the remainder by 10 and divide this result by the denominator to determine the thousandth digit:

$\frac{100}{15} = 6$

Then,

$\frac{1}{15} = 0.666$

This question asks us to write a decimal correct to 2 decimal places, which has the characteristic that is infinite periodical decimal. Then, the result correct to 2 decimal places is:

$\frac{1}{15} = 0.\overline{66}$

3 0

2 years ago

Distance between two points (−5,−5) and (-9, -2)

sergey [27]

Answer: 5

Step-by-step explanation: d = √(x^²-x^₁)^2+(y^²-y^₁)^2 d = √ (-9--5)^2+ (-2 - -5)^2 d = √(-4)^2 + (3)^2 d = √16 + 9 d = √25 d = 5

8 0

2 years ago

The circumference of a sphere was measured to be 80 cm with a possible error of 0.5 cm. A) Use differentials to estimate the max

siniylev [52]

Answer:

A) The maximum error in the calculated surface area: $25cm^2$

Relative error: $0.013$

B) The maximum error in the calculated volume: $162cm^2$

Relative error: $0.019$

Step-by-step explanation:

A) The formula for the surface area is:

$A=4\pi r^2$

The measured value is the circumference which is equal to:

$C=2\pi r$

then the radius is:

$r=\frac{C}{2\pi}$

Substituting in the formula of the surface:

$A=4\pi(\frac{C}{2\pi})^2\\A=4\pi(\frac{C^2}{4\pi^2})\\A=\frac{C^2}{\pi}$

Using the formula to calculate the error:

$dy=f'(x)dx$

Where $x$ is the variable measured and $y$ is a function of $x$ ( $y=f(x)$ ).

$dA=f'(C)dC\\dA=\frac{2C^{(2-1)}}{\pi}dC\\dA=\frac{2C}{\pi}dC$

We have C=80cm and dC=0.5cm

$dA=\frac{2C}{\pi}dC\\dA=\frac{2(80)}{\pi}(0.5)\\dA=\frac{160}{\pi}(0.5)\\dA=50.9296(0.5)\\dA=25.4648\approx25cm^2$

The relative error is the maximum error divide by the total area. The total area is: $A=\frac{C^2}{\pi}=\frac{(80)^2}{\pi}=\frac{6400}{\pi}=2037.1833cm^2$

$\frac{dA}{A}=\frac{25.4648}{2037.1833} =0.0125\approx0.013$

B) The formula for the volume is:

$V=\frac{4}{3} \pi r^3$

Using $r=\frac{C}{2\pi}$

$V=\frac{4}{3} \pi r^3\\V=\frac{4}{3} \pi (\frac{C}{2\pi})^3\\V=\frac{4}{3} \pi (\frac{C^3}{8\pi^3})\\V=\frac{1}{3}(\frac{C^3}{2\pi^2})\\V=\frac{C^3}{6\pi^2}$

The maximum error is:

$dV=\frac{3C^{3-1}}{6\pi^2}dC\\dV=\frac{C^{2}}{2\pi^2}dC\\dV=\frac{(80)^{2}}{2\pi^2}(0.5)\\dV=\frac{6400}{2\pi^2}(0.5)\\dV=\frac{6400}{2\pi^2}(0.5)\\dV=(324.2278)(0.5)\\dV=162.1139\approx162cm^2$

The calculated volume is:

$V=\frac{C^3}{6\pi^2}\\V=\frac{(80)^3}{6\pi^2}\\V=\frac{512000}{6\pi^2}\\V=8646.0743$

The relative error is:

$\frac{dV}{V}=\frac{162.1139}{8646.0743}=0.0188\approx0.019$

3 0

2 years ago

A gardener has a cylindrical planter that has a radius of 12 inches and is 2 feet deep what is the approximate number of cubic f

kobusy [5.1K]

Answer:

2 feet of soil

Step-by-step explanation:

8 0

3 years ago

Community Gym charges a $50 membership fee and a $70 monthly fee. Workout Gym charges a $190

zepelin [54]

Answer:

14 month

Step-by-step explanation:

Lets create equations for these two gyms. I believe this is an algebra 1 problem.

Community Gym: y=70x+50

Workout Gym: y=60x+190

Because both gyms are equal to y, we can set them together and solve for x.

70x+50=60x+190

10x=140

x=14

You can find the cost by plugging in 14 into both of the equations. You get a cost of $1030 after 14 months

Therefore, after 14 months you will have paid the same amount for both gyms.

7 0

3 years ago

(1000÷1)×10-5000 Giving brainliest​

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