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Nonamiya [84]
2 years ago
5

HELLLPPPP PLEEEAAASE

Mathematics
1 answer:
Ipatiy [6.2K]2 years ago
6 0
Alternate interior angles of parallel lines are congruent

k + 5 = 126

k = 121°
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Suppose EG=3​, EB=8​, A(F)=7​, m∠EBG=23​, m∠EGF=32​, and m∠CAE=51. Find m∠CAF.
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Answer:

m∠CAF is 28°

Step-by-step explanation:

The given parameters are;

EG = 3, EB = 8, A_F = 7, m∠EBG = 23°, ∠EGF 32°, and m∠CAE = 51°

From the diagram, we have;

m∠EBG = m∠EAD ;                {}                                    Given

Therefore, m∠EAD = 23°  

m∠CAE = m∠CAF + m∠EAD {}                                     Angle addition postulate

Therefore, we have;

51° = m∠CAF + 23° {}                        

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m∠CAF = 28°

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4 years ago
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