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2 years ago

Find f (25/29) if f (x)=-5x+5

Mathematics

1 answer:

devlian [24]2 years ago

5 0

Answer:

f(25/29) = $\frac{20}{29}$

Step-by-step explanation:

In order to do this problem, we need to plug in $\frac{25}{29}$ for x. When we plug it in we get $f(x) = -5(\frac{25}{29}) + 5$ . After this we can start by multiplying. When we multiply $-5(\frac{25}{29} )$ we get $(\frac{-125}{29}) + 5$ . Since the fraction cannot be simplified any further, we can now add 5. In order to add 5 we need to find a common denominator, which in this case will be 29. Changing the denominator to 29 gives us $(\frac{-125}{29}) + \frac{145}{29}$ because when changing the denominator we have to multiply the numerator by the same number. After adding these fractions we get our answer of $\frac{20}{29}$ .

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Find the slope of the line through each pair of points. Pls help and explain if you cann!!

Lady bird [3.3K]

Answer:

1) The slope for the given points (6,7) and (-10,4) is $m=\frac{3}{16}$

2) The slope for the given points (17,4) and (13,20) is $m=-4$

3) The slope for the given points (12,19) and (14,18) is $m=-\frac{1}{2}$

4) The slope for the given points (-11,0) and (18,13) is $m=\frac{13}{29}$

5) The slope for the given points (3,6) and (-8,20) is $m=-\frac{14}{11}$

6) The slope for the given points (-16,-20) and (12,5) is $m=\frac{25}{28}$

7) The slope for the given points (13,20) and (14,-14) is $m=-34$

8) The slope for the given points (18,15) and (3,0) is $m=1$

Step-by-step explanation:

To find the slope of the line through each pair of points:

1) Given points are (6,7) and (-10,4)

The slope formula is $m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}$

Let $(x_{1},y_{1})$ and $(x_{2},y_{2})$ be the given points (6,7) and (-10,4) respectively

$m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}$

$m=\frac{4-7}{-10-6}$

$m=\frac{-3}{-16}$

$m=\frac{3}{16}$

Therefore the slope for the given points (6,7) and (-10,4) is $m=\frac{3}{16}$

2) Given points are (17,4) and (13,20)

The slope formula is $m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}$

Let $(x_{1},y_{1})$ and $(x_{2},y_{2})$ be the given points (17,4) and (13,20) respectively

$m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}$

$m=\frac{20-4}{13-17}$

$m=\frac{16}{-4}$

$m=-4$

Therefore the slope for the given points (17,4) and (13,20) is $m=-4$

3) Given points are (12,19) and (14,18)

The slope formula is $m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}$

Let $(x_{1},y_{1})$ and $(x_{2},y_{2})$ be the given points (12,19) and (14,18) respectively

$m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}$

$m=\frac{18-19}{14-12}$

$m=\frac{-1}{2}$

Therefore the slope for the given points (12,19) and (14,18) is $m=-\frac{1}{2}$

4) Given points are (-11,0) and (18,13)

The slope formula is $m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}$

Let $(x_{1},y_{1})$ and $(x_{2},y_{2})$ be the given points (-11,0) and (18,13) respectively

$m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}$

$m=\frac{13-0}{18-(-11)}$

$m=\frac{13}{29}$

Therefore the slope for the given points (-11,0) and (18,13) is $m=\frac{13}{29}$

5) Given points are (3,6) and (-8,20)

The slope formula is $m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}$

Let $(x_{1},y_{1})$ and $(x_{2},y_{2})$ be the given points (3,6) and (-8,20) respectively

$m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}$

$m=\frac{20-6}{-8-3}$

$m=\frac{14}{-11}$

$m=-\frac{14}{11}$

Therefore the slope for the given points (3,6) and (-8,20) is $m=-\frac{14}{11}$

6) Given points are (-16,-20) and (12,5)

The slope formula is $m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}$

Let $(x_{1},y_{1})$ and $(x_{2},y_{2})$ be the given points (-16,-20) and (12,5) respectively

$m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}$

$m=\frac{5-(-20)}{12-(-16)}$

$m=\frac{5+20}{12+16}$

$m=\frac{25}{28}$

Therefore the slope for the given points (-16,-20) and (12,5) is $m=frac{25}{28}$

7) Given points are (13,20) and (14,-14)

The slope formula is $m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}$

Let $(x_{1},y_{1})$ and $(x_{2},y_{2})$ be the given points (13,20) and (14,-14) respectively

$m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}$

$m=\frac{-14-20)}{14-13}$

$m=\frac{-34}{1}$

$m=-34$

Therefore the slope for the given points (13,20) and (14,-14) is $m=-34$

8) Given points are (18,15) and (3,0)

The slope formula is $m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}$

Let $(x_{1},y_{1})$ and $(x_{2},y_{2})$ be the given points (18,15) and (3,0) respectively

$m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}$

$m=\frac{0-15}{3-18}$

$m=\frac{-15}{-15}$

$m=1$

Therefore the slope for the given points (18,15) and (3,0) is $m=1$

8 0

2 years ago

I need help, i don’t understand this.

Marina86 [1]

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answer
A. -8

3 0

3 years ago

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