Answer:for ax^2+bx+c=0 the discriminant is b^2-4ac
there are 3 basic cases of what happens for different discriminants
1. if the discriminant is less than 0, then there are no real zeroes
2. if the discriminant is 0, then it has 1 zero
3. if the discriminant is greater than 0, it has 2 zeroes
so given
0=3x^2-7x+4
a=3,b=-7,c=4
thus the discriminant is (-7)^2-4(3)(4)=49-48=1
the discriminant is 1. 1 is positive, thus the equation has 2 zeroes because the discriminant is greater than 0
the answer is the equation has two zeroes because the discriminant is greater than 0
Step-by-step explanation:
Answer:$26
Step-by-step explanation:you do the problem in reverse adding when it says spends and multiplying when it says half. she has $1 dollar left if you work in reverse you then add $3 and get $4. then add $2 and get $6 then multiply that by 2 getting $12. you then add $1 and get $13 then the last step is multiplying and you get $26. hope this helps
4,6,7,11,15,16 this would be the answer!