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nexus9112 [7]
3 years ago
12

Find f (25/29) if f (x)=-5x+5

Mathematics
1 answer:
devlian [24]3 years ago
5 0

Answer:

f(25/29) = \frac{20}{29}

Step-by-step explanation:

In order to do this problem, we need to plug in \frac{25}{29} for x. When we plug it in we get f(x) = -5(\frac{25}{29}) + 5. After this we can start by multiplying. When we multiply -5(\frac{25}{29} ) we get (\frac{-125}{29}) + 5. Since the fraction cannot be simplified any further, we can now add 5. In order to add 5 we need to find a common denominator, which in this case will be 29. Changing the denominator to 29 gives us (\frac{-125}{29}) + \frac{145}{29} because when changing the denominator we have to multiply the numerator by the same number. After adding these fractions we get our answer of \frac{20}{29}.

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Jay gas $8 he wants to buy a book gir $7.50 the sales tax 6% does he have enough money
Reil [10]
6%=0.06
if you want to know how much he paid for the sales taxes you multiply 7.5 by 0.06 
7.5 . 0.06= 0.45
7.5+0.45=7.95
8>7.95
Jay have enough money to buy the book
8 0
3 years ago
The perimeter of equilateral triangle ABC is 81/3 centimeters, find the length of the radius and apothem.
MAXImum [283]

There is a typo error, the perimeter of equilateral triangle ABC is 81/√3 centimeters.

Answer:

Radius = OB= 27 cm

Apothem = 13.5 cm

A diagram is attached for reference.

Step-by-step explanation:

Given,

The perimeter of equilateral triangle ABC is 81/√3 centimeters.

Substituting this in the formula of perimeter of equilateral triangle =3\times\ side

3\times\ side =[tex]81\sqrt{3}

Side = \frac{81\sqrt{3} }{3} =27\sqrt{3} \ cm

Thus from the diagram , Side AB=BC=AC= 27\sqrt{3} \ cm

We know each angle of an equilateral triangle is 60°.

From the diagram, OB is an angle bisector.

Thus \angle OBC = 30°

Apothem is the line segment from the mid point of any side to the center the equilateral triangle.

Therefore considering ΔOBE, and applying tan function.

tan\theta =\frac{perpendicular}{base} \\tan\theta=\frac{OE}{BE} \\tan\theta=\frac{OE}{\frac{27\sqrt{3}}{2}  } \\tan30\times {\frac{27\sqrt{3} }{2} }= OE\\\frac{1}{\sqrt{3} } \times\frac{27\sqrt{3} }{2} =OE\\

Thus ,apothem  OE= 13.5 cm

Now for radius,

We consider ΔOBE

cos\theta=\frac{base}{hypotenuse} \\cos30= \frac{BE}{OB} \\Cos30 = \frac{\frac{27\sqrt{3} }{2}}{OB}  \\OB= \frac{\frac{27\sqrt{3} }{2}}{cos30} \\OB= \frac{\frac{27\sqrt{3} }{2}}{\frac{\sqrt{3} }{2} } \\OB =27 \ cm

Thus for

Perimeter of equilateral triangle ABC is 81/√3 centimeters,

The radius of equilateral triangle ABC is 27 cm

The apothem of equilateral triangle ABC is 13.5 cm

4 0
3 years ago
Can somebody help me with this pretest
Ann [662]

Answer:

yes, I can help you do it.

8 0
3 years ago
I need help with the equation I know what the value of x is . Also their is only one equation .
Sindrei [870]
40+90=130
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3 0
3 years ago
Adiya said that the first step to solving the quadratic equation x2 + 6 = 20x by completing the square was to divide 6 by 2, squ
vivado [14]

Adiya’s method is not correct. To form a perfect square trinomial, the constant must be isolated on one side of the equation. Also, the coefficient of the term with an exponent of 1 on the variable is used to find the constant in the perfect square trinomial. Adiya should first get the 20x term on the same side of the equation as x2. Then she would divide 20 by 2, square it, and add 100 to both sides.


5 0
3 years ago
Read 2 more answers
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