Ask question

Ask question

All categories

2 years ago

11

Olivia deposits $6,952 in a savings account paying 3.72% interest. To the nearest dollar, how much money does Olivia have in tot

al after sixteen years?a.$4,138b.$8,568c.$11,090d.$29,901

2 answers:

liubo4ka [24]2 years ago

6 0

Answer:

C on EDGE 2021

Step-by-step explanation:

ivolga24 [154]2 years ago

4 0

Answer:

11090

Step-by-step explanation:

6952x.0372=258.61

258.61x16=4137.83

4137.83+6952=11090

You might be interested in

25 Points! Please Help Me With This. Click On The Photo And Can You Please Help Me Answer #4 I Do Not Get What It Means. If You

barxatty [35]

Answer:

So both equations are true

Step-by-step explanation:

#4 was asking you to substitute x = 4 into both equations to see if it's the solution of the equations.

Substitute x = 4

Ritz equation

y = 30x + 20

y = 30(4) + 20

y = 120 + 20

y = 140

Smits equation:

y = 15x + 80

y = 15(4) + 80

y = 60 + 80

y = 140

Both companies charged same price $140 for 4 days

So both equations are true

5 0

3 years ago

Read 2 more answers

PLZ help me this is hard

Assoli18 [71]

Answer:

d

Step-by-step explanation:

4 0

3 years ago

Simplify the following expression: (2x2+3x−4)−(4x2−7x+1)

Olegator [25]

The answer for this problem is B

6 0

3 years ago

Find the volume V of the solid obtained by rotating the region bounded by the given curves about the specified line.? y = 2 + se

sertanlavr [38]

Answer:

The volume of the solid is: $\mathbf{V = \pi [ \dfrac{8 \pi}{3} - 2\sqrt{3}]}$

Step-by-step explanation:

GIven that :

$y = 2 + sec \ x , -\dfrac{\pi}{3} \leq x \leq \dfrac{\pi}{3} \\ \\ y = 4\\ \\ about \ y \ = 2$

This implies that the distance between the x-axis and the axis of the rotation = 2 units

The distance between the x-axis and the inner ring is r = (2+sec x) -2

Let R be the outer radius and r be the inner radius

By integration; the volume of the of the solid can be calculated as follows:

$V = \pi \int\limits^{\dfrac{\pi}{3}}_{\dfrac{-\pi}{3}} [(4-2)^2 - (2+ sec \ x -2)^2]dx \\ \\ \\ V = \pi \int\limits^{\dfrac{\pi}{3}}_{\dfrac{-\pi}{3}} [(2)^2 - (sec \ x )^2]dx \\ \\ \\ V = \pi \int\limits^{\dfrac{\pi}{3}}_{\dfrac{-\pi}{3}} [4 - sec^2 \ x ]dx$

$V = \pi [4x - tan \ x]^{\dfrac{\pi}{3}}_{\dfrac{-\pi}{3}} \\ \\ \\ V = \pi [4(\dfrac{\pi}{3}) - tan (\dfrac{\pi}{3}) - 4(-\dfrac{\pi}{3})+ tan (-\dfrac{\pi}{3})] \\ \\ \\ V = \pi [4(\dfrac{\pi}{3}) - tan (\dfrac{\pi}{3}) + 4(\dfrac{\pi}{3})- tan (\dfrac{\pi}{3})] \\ \\ \\ V = \pi [8(\dfrac{\pi}{3}) - 2 \ tan (\dfrac{\pi}{3}) ]$

$\mathbf{V = \pi [ \dfrac{8 \pi}{3} - 2\sqrt{3}]}$

7 0

3 years ago

PLEASE HELP!!!!

lidiya [134]

1.4 or 0.5 hope this helps

5 0

3 years ago

Read 2 more answers