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Afina-wow [57]
3 years ago
13

It takes you 8 hours to dig a hole. It would take you and your brother 5 hours to dig that same hile together. If your brother w

as to dig the hole by himself it would take him how many hours?
Mathematics
2 answers:
inn [45]3 years ago
6 0

Answer:

I think if it takes me 8 hours then it will surely take him 8 hours

DerKrebs [107]3 years ago
4 0

Answer:

40/3 hrs = 13.3 hrs

Step-by-step explanation:

Let me = K , my brother = P

K digs a hole in 8 hrs

K in 1 hr digs 1/8 of a hole

K + P dig a hole in 5 hrs

K + P in 1 hr dig 1/5

Let the portion of the hole Plan digs in 1 hr be x

1/8 + x = 1/5

x = 3/40

3/40 of the hole is dug by P in 1 hr

1 of the hole is dug by P in 40/3 hrs

= 40/3 hrs

=13.3 hrs

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\qquad \qquad\huge \underline{\boxed{\sf Answer}}

Here's the solution ~

Let's find the measure of hypotenuse first, by using Pythagoras theorem ;

\qquad \sf  \dashrightarrow \: h {}^{2}  =  {8}^{2}  +  {6}^{2}

\qquad \sf  \dashrightarrow \: h {}^{2}  =  {36}^{}  +  {64}^{}

\qquad \sf  \dashrightarrow \: h {}^{2}  = 100

\qquad \sf  \dashrightarrow \: h {}^{}  =  \sqrt{100}

\qquad \sf  \dashrightarrow \: h {}^{}  =  {10}

Now, let's find the asked values ~

\qquad \sf  \dashrightarrow \:  \sin(x) =  \dfrac{opposite \: side}{hypotenuse}

\qquad \sf  \dashrightarrow \:  \sin(x) =  \dfrac{6}{10}

\qquad \sf  \dashrightarrow \:  \sin(x) =  \dfrac{3}{5}   \: or \: 0.6 \: units

For Cos y :

\qquad \sf  \dashrightarrow \:  \cos(y) =  \dfrac{adjcant \: side}{hypotenuse}

\qquad \sf  \dashrightarrow \:  \cos(y)   = \dfrac{6}{10}

\qquad \sf  \dashrightarrow \:  \cos(y)   = \dfrac{3}{5}  \: or \: 0.6 \: units

As we can see that both sin x and Cos y have equal values, therefore The required relationships is equality.

I.e Sin x = Cos y

Hope it helps ~

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