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3 years ago

Which of these numbers has five significant numbers?

Mathematics

2 answers:

Yakvenalex [24]3 years ago

7 0

Answer:

Step-by-step explanation:

A has 9 sig digits. Every digit counts including the 4 zeros, because 3 digits follow them. Even if the 345 were not there, there still are 6 sig digits.

B. Those two trailing zeros mean something. They are guaranteed place holders. This number has 7 sig digs.

D. Depends on who teaches this. 5 without a period at the end means that the number is exactly 5 -- or that's the rule when I was teaching.

The answer is C, believe it or not. Again, those zeros are place holders. They are guaranteed to be accurate. This is a question to look at carefully.

Scrat [10]3 years ago

6 0

Hello There!

1.0000 has 5 significant digits.

The zeros at the end of a decimal are significant.

Hope this helps you!

~Just a felicitous girlie

#HaveASplendidDay

$SilentNature :)$

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Read 2 more answers

Evaluate when a = 8 and b = 4. ab^2 a−b

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Evaluate when a = 8 and b = 4.

ab^2
a−b

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3 years ago

The measurenicnt of the circumference of a circle is found to be 56 centimeters. The possible error in measuring the circumferen

BartSMP [9]

Answer:

(a) Approximate the percent error in computing the area of the circle: 4.5%

(b) Estimate the maximum allowable percent error in measuring the circumference if the error in computing the area cannot exceed 3%: 0.6 cm

Step-by-step explanation:

(a)

First we need to calculate the radius from the circumference:

$c=2\pi r\\r=\frac{c}{2\pi } \\c=8.9 cm$

I leave only one decimal as we need to keep significative figures

Now we proceed to calculate the error for the radius:

$\Delta r=\frac{dt}{dc} \Delta c\\\\\frac{dt}{dc} = \frac{1}{2 \pi } \\\\\Delta r=\frac{1}{2 \pi } (1.2)\\\\\Delta r= 0.2 cm$

$r = 8.9 \pm 0.2 cm$

Again only one decimal because the significative figures

Now that we have the radius, we can calculate the area and the error:

$A=\pi r^{2}\\A=249 cm^{2}$

Then we calculate the error:

$\Delta A= (\frac{dA}{dr} ) \Delta r\\\\\Delta A= 2\pi r \Delta r\\\\\Delta A= 11.2 cm^{2}$

$A=249 \pm 11.2 cm^{2}$

Now we proceed to calculate the percent error:

$\%e =\frac{\Delta A}{A} *100\\\\\%e =\frac{11.2}{249} *100\\\\\%e =4.5\%$

(b)

With the previous values and equations, now we set our error in 3%, so we just go back changing the values:

$\%e =\frac{\Delta A}{A} *100\\\\3\%=\frac{\Delta A}{249} *100\\\\\Delta A =7.5 cm^{2}$

Now we calculate the error for the radius:

$\Delta r= \frac{\Delta A}{2 \pi r}\\\\\Delta r= \frac{7.5}{2 \pi 8.9}\\\\\Delta r= 0.1 cm$

Now we proceed with the error for the circumference:

$\Delta c= \frac{\Delta r}{\frac{1}{2\pi }} = 2\pi \Delta r\\\\\Delta c= 2\pi 0.1\\\\\Delta c= 0.6 cm$

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